The factor that favors the formation of II product in preference to III from trans-decalin derivative is to be determined. Concept introduction: Decalin is a colorless liquid with an aromatic odor. It has molecular formula C 10 H 18 . The molar mass of decalin is 138.25 g/mol. If the steric hindrance in a compound is less, then the stability of the product is more. Steric hindrance of a product increases because of the presence of more bulky groups at the same position. In double bond or cyclic compounds, if two same functional groups are present on the same side of the double bond or cyclic compound, the given compound can be labeled as cis. If the two functional groups are present on the different sides of the double bond or cyclic compound, the given compound can be labeled as Trans.

Question

Want to see the full answer?

Answer 1

Question

Chapter 11, Problem 51P

Interpretation Introduction

Interpretation:

The factor that favors the formation of II product in preference to III from trans-decalin derivative is to be determined.

Concept introduction:

Decalin is a colorless liquid with an aromatic odor. It has molecular formula C10H18.

The molar mass of decalin is 138.25 g/mol.

If the steric hindrance in a compound is less, then the stability of the product is more.

Steric hindrance of a product increases because of the presence of more bulky groups at the same position.

In double bond or cyclic compounds, if two same functional groups are present on the same side of the double bond or cyclic compound, the given compound can be labeled as cis.

If the two functional groups are present on the different sides of the double bond or cyclic compound, the given compound can be labeled as Trans.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

Alkenes can be converted to alcohols by hydroboration-oxidation. (a) Draw the structure of the alcohol or alcohols formed in the reaction sequence. Clearly indicate stereochemistry by drawing a wedged bond, a dashed bond and two in-plane bonds per each chiral carbon. Draw hydrogen atoms that are connected to wedge-and-dash bonds.(b) Characterize the product or products of the reactions. Be sure to draw hydrogens on oxygen, where applicable. Select Draw Rings More Erase H 1. B,H§, diglyme (a) 2. H2O2, HO", H2O

Alkenes can be converted to alcohols by hydroboration-oxidation. (a) Draw the structure of the alcohol or alcohols formed in the reaction sequence. Clearly indicate stereochemistry by drawing a wedged bond, a dashed bond and two in-plane bonds per each chiral carbon. Draw hydrogen atoms that are connected to wedge-and-dash bonds.(b) Characterize the product or products of the reactions. Be sure to draw hydrogens on oxygen, where applicable. Select Draw Rings More Erase H 1. B₂H6, (a) diglyme 2. H2O2, HOT, H₂O ✓ C O Q2 Q

Alkenes can be converted to alcohols by hydroboration-oxidation. (a) Draw the structure of the alcohol or alcohols formed in the reaction sequence. Clearly indicate stereochemistry by drawing a wedged bond, a dashed bond and two in-plane bonds per each chiral carbon. Draw hydrogen atoms that are connected to wedge-and-dash bonds.(b) Characterize the product or products of the reactions. Be sure to draw hydrogens on oxygen, where applicable. H 1. B2H6. diglyme (a) H 2. H2O2, HO-, H20 он OH Incorrect