Chapter 11, Problem 48A

When aluminum is mixed with iron(lll) oxide, iron metal and aluminum oxide are produced, along with a large quantity of heat. What mole ratio would you use to determine moles of Fe if moles of ${\text{Fe}}_{\text{2}}{\text{O}}_{\text{3}}$ is known?
   ${\text{Fe}}_{\text{2}}{\text{O}}_{\text{3}}\left(\text{s}\right)\text{ + 2A1}\left(\text{s}\right)\to \text{ 2Fe}\left(\text{s}\right){\text{ + A1}}_{\text{2}}{\text{O}}_{\text{3}}\left(\text{s}\right)\text{ + heat}$

Interpretation Introduction

Interpretation:

The mole ratio for Fe and $F{e}_2{O}_3$ in the given chemical equation needs to be determined.

Concept introduction:

Mole ratio is conversion factor which is used to determine the ratio in which the given substances are reacting in a balanced chemical equation.

Answer to Problem 48A

Balanced chemical equation: ${\text{Fe}}_{\text{2}}{\text{O}}_{\text{3}}\text{+2Al}\underset{}{\overset{}{\to }}{\text{Al}}_{\text{2}}{\text{O}}_{\text{3}}\text{+2Fe+Heat}$

Thus, mole ratio is $\frac{2moleFe}{1moleF{e}_2{O}_3}$

Explanation of Solution

The given balanced chemical equation is as follows:

${\text{Fe}}_{\text{2}}{\text{O}}_{\text{3}}\text{+2Al}\underset{}{\overset{}{\to }}{\text{Al}}_{\text{2}}{\text{O}}_{\text{3}}\text{+2Fe+Heat}$

Here, 1 mol of ${\text{Fe}}_{\text{2}}{\text{O}}_{\text{3}}$ gives 2 mol of Fe.

Thus, mole ratio will be:

$\frac{2molFe}{1molF{e}_2{O}_3}$