Chapter 1.1, Problem 24AYU

To determine

The distance between the given points

Answer to Problem 24AYU

  $d\left(P_1,P_2\right)=3\sqrt{3}\text{units}$

Explanation of Solution

Given:

The given points are

  $\begin{array}{l}{P}_1=\left(2,-3\right)\\ P_2=\left(4,2\right)\end{array}$

Calculation:

The distance between two points $P_1=\left(x_1,y_1\right)\text{and }{P}_2=\left(x_2,y_2\right)$ can be calculated as

  $d\left(P_1,P_2\right)=\sqrt{{\left(x_2-x_1\right)}^2+{\left(y_2-y_1\right)}^2}$

The distance can be calculated as

  $\begin{array}{l}d\left(P_1,P_2\right)=\sqrt{{\left(4-2\right)}^2+{\left(2-\left(-3\right)\right)}^2}\\ d\left(P_1,P_2\right)=\sqrt{{\left(2\right)}^2+{\left(5\right)}^2}\\ d\left(P_1,P_2\right)=\sqrt{4+25}\\ d\left(P_1,P_2\right)=\sqrt{27}\\ d\left(P_1,P_2\right)=3\sqrt{3}\text{units}\end{array}$