Electricity Rates in Florida Florida Power & Light Company supplies electricity to residential customers for a monthly customer charge of $ 8.01 plus 8.89 cents per kilowatt hour (kWh) for up to 1000 kilowatt hours. Write a linear equation that relates the monthly charge C , in dollars, to the number x of kilowatt hours used in a month, 0 ≤ x ≤ 1000. Graph this equation. What is the monthly charge for using 200 kilowatt hours? What is the monthly charge for using 500 kilowatt hours? Interpret the slope of the line.
Electricity Rates in Florida Florida Power & Light Company supplies electricity to residential customers for a monthly customer charge of $ 8.01 plus 8.89 cents per kilowatt hour (kWh) for up to 1000 kilowatt hours. Write a linear equation that relates the monthly charge C , in dollars, to the number x of kilowatt hours used in a month, 0 ≤ x ≤ 1000. Graph this equation. What is the monthly charge for using 200 kilowatt hours? What is the monthly charge for using 500 kilowatt hours? Interpret the slope of the line.
Electricity Rates in Florida Florida Power & Light Company supplies electricity to residential customers for a monthly customer charge of
$
8.01
plus
8.89
cents per kilowatt hour (kWh) for up to
1000
kilowatt hours.
Write a linear equation that relates the monthly charge
C
, in dollars, to the number
x
of kilowatt hours used in a month,
0
≤
x
≤
1000.
Graph this equation.
What is the monthly charge for using
200
kilowatt hours?
What is the monthly charge for using
500
kilowatt hours?
Interpret the slope of the line.
(a)
Expert Solution
To determine
A linear equation representing relation between the monthly charge C in dollars, and the number x of kilowatt hours used in a month 0≤x≤1000, ifelectricity is supplied for a monthly customer charge of $8.01 plus 8.89¢ per kilowatt hour (kWh) for up to 1000 kilowatt hours.
Answer to Problem 119AYU
Solution:
A linear equation that relates the monthly charge C in dollars, to the number x of kilowatt hours used in a month 0≤x≤1000 is C(x)=0.0889x+8.01
Explanation of Solution
Given Information:
Florida Power & Light Company supplies electricity to residential customers for a monthly customer charge of $8.01 plus 8.89¢ per kilowatt hour (kWh) for up to 1000 kilowatt hours.
Explanation:
First, convert 8.89¢ in dollar.
1$=100¢.
Thus, divide 8.89 by 100.
⇒8.89100=0.0889
Therefore, 8.89¢ is equal to 0.0889$.
Number of kilowatt hours used in a month is x.
Thus, the cost for x kilowatt per houris 0.0889⋅x.
So the linear equation that relates the monthly charge C in dollars, to the number x of kilowatt hours used in a month 0≤x≤1000 is,
C(x)=0.0889x+8.01
(b)
Expert Solution
To determine
To graph: The linear equation that relates the monthly charge C in dollars, to the number x of kilowatt hours used in a month 0≤x≤1000, ifelectricity is supplied for a monthly customer charge of $8.01 plus 8.89¢ per kilowatt hour (kWh) for up to 1000 kilowatt hours.
Explanation of Solution
Given Information:
Florida Power & Light Company supplies electricity to residential customers for a monthly customer charge of $8.01 plus 8.89 cents per kilowatt hour (kWh) for up to 1000 kilowatt hours.
Graph:
From part (a), the linear equation that relates the monthly charge C in dollars, to the number x of kilowatt hours used in a month 0≤x≤1000. C(x)=0.0889x+8.01.
The graph is as follows;
Interpretation:
The graph shows the graph of the linear equation C(x)=0.0889x+8.01.
(c)
Expert Solution
To determine
The monthly charge for using 200 kilowatt hours, ifelectricity is supplied for a monthly customer charge of $8.01 plus 8.89¢ per kilowatt hour (kWh) for up to 1000 kilowatt hours.
Answer to Problem 119AYU
Solution:
The monthly charge for using 200 kilowatt hours is 25.79.
Explanation of Solution
Given Information:
Florida Power & Light Company supplies electricity to residential customers for a monthly customer charge of $8.01 plus 8.89 cents per kilowatt hour (kWh) for up to 1000 kilowatt hours.
Explanation:
From part (a), the linear equation that represents the relation between the monthly charge C in dollars, and the number x of kilowatt hours used in a month 0≤x≤1000 is C(x)=0.0889x+8.01.
To find the monthly charge for using 200 kilowatt hours, plug x=200 in linear equation C(x)=0.0889x+8.01.
Thus, C(x)=0.0889(200)+8.01
⇒C(x)=17.78+8.01
⇒C(x)=25.79
Thus, the monthly charge for using 200 kilowatt hours is 25.79.
(d)
Expert Solution
To determine
The monthly charge for using 500 kilowatt hours. If electricity is supplied for a monthly customer charge of $8.01 plus 8.89¢ per kilowatt hour (kWh) for up to 1000 kilowatt hours.
Answer to Problem 119AYU
Solution:
The monthly charge for using 500 kilowatt hours is 52.46.
Explanation of Solution
Given Information:
Florida Power & Light Company supplies electricity to residential customers for a monthly customer charge of $8.01 plus 8.89 cents per kilowatt hour (kWh) for up to 1000 kilowatt hours.
Explanation:
From part (a), the linear equation that represents the relation between the monthly charge C in dollars and the number x of kilowatt hours used in a month 0≤x≤1000 is C(x)=0.0889x+8.01.
To find the monthly charge for using 500 kilowatt hours, plug x=500 in linear equation C(x)=0.0889x+8.01.
Thus, C(x)=0.0889(500)+8.01
⇒C(x)=44.45+8.01
⇒C(x)=52.46
Thus, the monthly charge for using 500 kilowatt hours is 52.46.
(e)
Expert Solution
To determine
The slope of the line, ifelectricity is supplied for a monthly customer charge of $8.01 plus 8.89¢ per kilowatt hour (kWh) for up to 1000 kilowatt hours.
Answer to Problem 119AYU
Solution:
The slope of the line is C(x)=0.0889x+8.01 is 0.0889.
Explanation of Solution
Given Information:
Florida Power & Light Company supplies electricity to residential customers for a monthly customer charge of $8.01 plus 8.89 cents per kilowatt hour (kWh) for up to 1000 kilowatt hours.
Explanation:
From part (a), the linear equation that represents the relation between the monthly charge C in dollars and the number x of kilowatt hours used in a month 0≤x≤1000. C(x)=0.0889x+8.01.
The slope point form of the equation of the line is y=mx+c where m is a slope and c is the y intercept.
The equation C(x)=0.0889x+8.01 is of the form y=mx+c.
Comparing the equation y=0.0889x+8.01 with y=mx+c,
⇒m=0.0889
Therefore, the slope of the line is C(x)=0.0889x+8.01 is 0.0889.
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