Answer Solution: (b) and (d) Explanation (a) (b) (c) (d) (e) The answer is (b) and (d).

Precalculus

9th Edition

ISBN: 9780321716835

Author: Michael Sullivan

Publisher: Addison Wesley

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Question

Chapter 1.3, Problem 132AYU

To determine

The figure shows the graph of two perpendicular lines. Which of the following pairs of equations might have such a graph?

(a) $y - 2 x = 2; y + 2 x = - 1$ (b) $y - 2 x = 0; 2 y + x = 0$

(c) $2 y - x = 2; 2 y + x = - 2$ (d) $y - 2 x = 2; x + 2 y = - 1$ (e) $2 x + y = - 2; 2 y + x = - 2$

Expert Solution & Answer

Answer to Problem 132AYU

Solution:

(b) and (d)

Explanation of Solution

(a)

Precalculus, Chapter 1.3, Problem 132AYU , additional homework tip 2

(b)

Precalculus, Chapter 1.3, Problem 132AYU , additional homework tip 3

(c)

Precalculus, Chapter 1.3, Problem 132AYU , additional homework tip 4

(d)

Precalculus, Chapter 1.3, Problem 132AYU , additional homework tip 5

(e)

Precalculus, Chapter 1.3, Problem 132AYU , additional homework tip 6

The answer is (b) and (d).

Chapter 1.3, Problem 131AYU

Chapter 1.3, Problem 133AYU

Chapter 1 Solutions

Precalculus

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The figure shows the graph of two perpendicular lines. Which of the following pairs of equations might have such a graph? (a) y − 2 x = 2 ; y + 2 x = − 1 (b) y − 2 x = 0 ; 2 y + x = 0 (c) 2 y − x = 2 ; 2 y + x = − 2 (d) y − 2 x = 2 ; x + 2 y = − 1 (e) 2 x + y = − 2 ; 2 y + x = − 2

Solution Summary: The author explains that the figure shows the graph of two perpendicular lines. Which of the following pairs of equations might have such a graph?

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The figure shows the graph of two perpendicular lines. Which of the following pairs of equations might have such a graph?

(a) $y - 2 x = 2; y + 2 x = - 1$ (b) $y - 2 x = 0; 2 y + x = 0$

(c) $2 y - x = 2; 2 y + x = - 2$ (d) $y - 2 x = 2; x + 2 y = - 1$ (e) $2 x + y = - 2; 2 y + x = - 2$

Answer to Problem 132AYU

Explanation of Solution

Chapter 1 Solutions

Additional Math Textbook Solutions

(a) $y - 2 x = 2; y + 2 x = - 1$	(b) $y - 2 x = 0; 2 y + x = 0$
(c) $2 y - x = 2; 2 y + x = - 2$	(d) $y - 2 x = 2; x + 2 y = - 1$	(e) $2 x + y = - 2; 2 y + x = - 2$

The figure shows the graph of two perpendicular lines. Which of the following pairs of equations might have such a graph? (a) y − 2 x = 2 ; y + 2 x = − 1 (b) y − 2 x = 0 ; 2 y + x = 0 (c) 2 y − x = 2 ; 2 y + x = − 2 (d) y − 2 x = 2 ; x + 2 y = − 1 (e) 2 x + y = − 2 ; 2 y + x = − 2

Solution Summary: The author explains that the figure shows the graph of two perpendicular lines. Which of the following pairs of equations might have such a graph?

Concept explainers

Videos

The figure shows the graph of two perpendicular lines. Which of the following pairs of equations might have such a graph? (a) y − 2x = 2; y + 2x = −1 (b) y − 2x = 0; 2y + x = 0 (c) 2y − x = 2; 2y + x = −2 (d) y − 2x = 2; x + 2y = −1 (e) 2x + y = −2; 2y + x = −2

Answer to Problem 132AYU

Explanation of Solution

Chapter 1 Solutions

Additional Math Textbook Solutions

The figure shows the graph of two perpendicular lines. Which of the following pairs of equations might have such a graph?

(a) $y - 2 x = 2; y + 2 x = - 1$ (b) $y - 2 x = 0; 2 y + x = 0$

(c) $2 y - x = 2; 2 y + x = - 2$ (d) $y - 2 x = 2; x + 2 y = - 1$ (e) $2 x + y = - 2; 2 y + x = - 2$