Concept explainers
(a)
Interpretation:
The structure of the alkene that could have been used to produce deuterated bromoalkene when treated with deuterium bromide (
Concept introduction:
The electrophilic addition of a Bronsted acid to the carbon-carbon double bond in
Answer to Problem 11.8P
The structure of the corresponding alkene that has been used to produce the given deuterated bromoalkane is
Explanation of Solution
The structure of the given bromoalkane is
In the structure above, the carbon atom to which the bromine atom is attached must be the carbon bearing the positive charge. Thus, a stable tertiary carbocation must have been formed during the mechanism. Deuterium is an isotope of hydrogen having similar chemical properties. When an alkene is treated with deuterium bromide, the first step of addition is that the deuterium gets attached to the doubly bonded carbon atom which has got a higher number of hydrogens attached (or least substituted). Thus, the carbon atom to which deuterium is attached must be having a double bond in the original alkene. The resulting carbocation that would form will be secondary and can rearrange to a more stable, tertiary carbocation via 1, 2-hydride shift. Thus, a less stable carbocation undergoes carbocation rearrangement reaction to form the most stable carbocation. In the next step, the bromine ion attacks this tertiary carbocation to form the given product. Thus, the structure of the corresponding alkene that could have been used to produce the given deuterated bromoalkane must be
The complete mechanism is shown below:
In an electrophilic addition reaction, the carbocation rearrangement reaction takes place to form a rearranged product.
(b)
Interpretation:
The structure of the alkene that could have been used to produce deuterated bromoalkene when treated with deuterium bromide (
Concept introduction:
The electrophilic addition of a Bronsted acid to the carbon-carbon double bond in alkenes is susceptible to carbocation rearrangements due to the stability of the carbocation. The carbocation rearrangement occurs via either 1, 2 hydride shift or 1, 2 methyl shift depending on the stability of the carbocation formed. The stability order for carbocation is benzylic > tertiary > secondary > primary > methyl etc. The normal electrophilic addition gives 1, 2-addition product, but due to the rearrangement reaction, the rearranged product may be formed instead of 1, 2-addition product. In the reaction of an alkene and hydrogen halide or deuterium halide, the carbon to which the deuterium is attached is the carbon bearing the positive charge. Further, the carbon atom to which the halide atom is attached must be the carbon bearing the positive charge, that is, carbocation intermediate. Rearrangements of the carbocation intermediate may be observed if a more stable carbocation is possible.
Answer to Problem 11.8P
The structure of the corresponding alkene that has been used to produce the given deuterated bromoalkane is
Explanation of Solution
The structure of the given bromoalkane is
In the structure above, the carbon atom to which the bromine atom is attached must be the carbon bearing the positive charge. Thus, a stable tertiary carbocation must have been formed during the mechanism. Deuterium is an isotope of hydrogen having similar chemical properties. When an alkene is treated with deuterium bromide, the first step of addition is that the deuterium gets attached to the doubly bonded carbon atom which has got a higher number of hydrogens attached (or least substituted). Thus, the carbon atom to which deuterium is attached must be having a double bond in the original alkene. The resulting carbocation that would form will be secondary and can rearrange to a more stable, tertiary carbocation via 1, 2-hydride shift. Thus, a less stable carbocation undergoes carbocation rearrangement reaction to form the most stable carbocation. In the next step, the bromine ion attacks this tertiary carbocation to form the given product.
Thus, the structure of the corresponding alkene that could have been used to produce the given deuterated bromoalkane must be
The complete mechanism is shown below:
In an electrophilic addition reaction, the carbocation rearrangement reaction takes place to form a rearranged product.
(c)
Interpretation:
The structure of the alkene that could have been used to produce deuterated bromoalkene when treated with deuterium bromide (
Concept introduction:
The electrophilic addition of a Bronsted acid to the carbon-carbon double bond in alkenes is susceptible to carbocation rearrangements due to the stability of the carbocation. The carbocation rearrangement occurs via either 1, 2 hydride shift or 1, 2 methyl shift depending on the stability of the carbocation formed. The stability order for carbocation is benzylic > tertiary > secondary > primary > methyl etc. The normal electrophilic addition gives 1, 2-addition product, but due to the rearrangement reaction, the rearranged product may be formed instead of 1, 2-addition product. In the reaction of an alkene and hydrogen halide or deuterium halide, the carbon to which the deuterium is attached is the carbon bearing the positive charge. Further, the carbon atom to which the halide atom is attached must be the carbon bearing the positive charge, that is, carbocation intermediate. Rearrangements of the carbocation intermediate may be observed if a more stable carbocation is possible.
Answer to Problem 11.8P
The structure of the corresponding alkene that has been used to produce the given deuterated bromoalkane is
Explanation of Solution
The structure of the given bromoalkane is
In the structure above, the carbon atom to which the bromine atom is attached must be the carbon bearing the positive charge. Thus, a stable tertiary carbocation must have been formed during the mechanism. Deuterium is an isotope of hydrogen having similar chemical properties. When an alkene is treated with deuterium bromide, the first step of addition is that the deuterium gets attached to the doubly bonded carbon atom, which has got a higher number of hydrogens attached (or least substituted). Thus, the carbon atom to which deuterium is attached must be having a double bond in the original alkene. The resulting carbocation that would form will be secondary and can rearrange to a more stable, tertiary carbocation via 1, 2-hydride shift. Thus, a less stable carbocation undergoes carbocation rearrangement reaction to form the most stable carbocation. In the next step, the bromine ion attacks this tertiary carbocation to form the given product.
Thus, the structure of the corresponding alkene that has been used to produce the given deuterated bromoalkane is
The complete mechanism is shown below:
In an electrophilic addition reaction, the carbocation rearrangement reaction takes place to form a rearranged product.
(d)
Interpretation:
The structure of the alkene that could have been used to produce deuterated bromoalkene when treated with deuterium bromide (
Concept introduction:
The electrophilic addition of a Bronsted acid to the carbon-carbon double bond in alkenes is susceptible to carbocation rearrangements due to the stability of the carbocation. The carbocation rearrangement occurs via either 1, 2 hydride shift or 1, 2 methyl shift depending on the stability of the carbocation formed. The stability order for carbocation is benzylic > tertiary > secondary > primary > methyl etc. The normal electrophilic addition gives 1, 2-addition product, but due to the rearrangement reaction, the rearranged product may be formed instead of 1, 2-addition product. In the reaction of an alkene and hydrogen halide or deuterium halide, the carbon to which the deuterium is attached is the carbon bearing the positive charge. Further, the carbon atom to which the halide atom is attached must be the carbon bearing the positive charge, that is, carbocation intermediate. Rearrangements of the carbocation intermediate may be observed if a more stable carbocation is possible.
Answer to Problem 11.8P
The structure of the corresponding alkene that has been used to produce the given deuterated bromoalkane is
Explanation of Solution
The structure of the given bromoalkane is
In the structure above, the carbon atom to which the bromine atom is attached must be the carbon bearing the positive charge. Thus, a stable tertiary carbocation must have been formed during the mechanism. Deuterium is an isotope of hydrogen having similar chemical properties. When an alkene is treated with deuterium bromide, the first step of addition is that the deuterium gets attached to the doubly bonded carbon atom, which has got a higher number of hydrogens attached (or least substituted). Thus, the carbon atom to which deuterium is attached must be having a double bond in the original alkene. The resulting carbocation that would form will be secondary and can rearrange to a more stable, tertiary carbocation via 1, 2-hydride shift. Thus, a less stable carbocation undergoes carbocation rearrangement reaction to form the most stable carbocation. In the next step, the bromine ion attacks this tertiary carbocation to form the given product.
Thus, the structure of the corresponding alkene that has been used to produce the given deuterated bromoalkane is
The mechanism for the reaction is shown below:
In an electrophilic addition reaction, the carbocation rearrangement reaction takes place to form a rearranged product.
Want to see more full solutions like this?
Chapter 11 Solutions
Organic Chemistry: Principles and Mechanisms (Second Edition)
- Please correct answer and don't used hand raitingarrow_forwardQ1: Curved Arrows, Bronsted Acids & Bases, Lewis Acids & Bases Considering the following reactions: a) Predict the products to complete the reactions. b) Use curved electron-pushing arrows to show the mechanism for the reaction in the forward direction. Redraw some of the compounds to explicitly illustrate all bonds that are broken and all bonds that are formed. c) Label Bronsted acids and bases in the left side of the reactions. Label conjugate acids and bases in the right side of the reactions. d) Label Lewis acids and bases, nucleophiles and electrophiles in the left side of the reactions. A. + OH CH30: OH B. + HBr C. H₂SO4 D. CF 3. CH 3 + HCI N H fluoxetine antidepressant 1↓ JDownloadarrow_forwardDon't used Ai solutionarrow_forward
- Part 3: AHm,system Mass of 1.00 M HCI Vol. of 1.00 M HCI Mass of NaOH(s) Total Mass in Calorimeter Mole product if HCI limiting reactant Trial 1 62.4009 1.511g Mole product if NaOH limiting reactant Limiting reactant Initial Temperature Final Temperature 23.8°C 37.6°C Change in Temperature AHm,system (calculated) Average AHm,system (calculated) (calculated) (calculated) Trial 2 64.006g 1.9599 (calculated) (calculated) (calculated) (calculated) (calculated) (calculated) 24.7°C 41.9°C (calculated) (calculated) (2 pts. each)arrow_forwardDon't used Ai solutionarrow_forwardWhat is the numerical value of the slope using the equation y=-1.823x -0.0162 please show calculationsarrow_forward
- Don't used hand raitingarrow_forward1.) Using the graph below (including the line equation of y = -1.823x - 0.0162) What is the numerical value for the slope shown? 2.) What are the Unit(s) associated with the slope of the line shown? for we all remember that numerical data always has units. 3.) What would be a good title for this graph and explain your choice. 0.00 0.0 02 0.4 10.6 08 10 12 -0.20 -0.40 -0.60 -0.80 Temp, freezing, in degrees Celcius 5-1.00 -1.20 -1.40 -1:60 y=-1.823x-0.0162 -180 -2.00 Concentration of Sucrose (m)arrow_forwardDon't used Ai solutionarrow_forward
- Identify the Functional Groups (FG) in the following molecules. Classify C atoms as tertiary, 30, or quaternary 40. Identify secondary 20 and tertiary, 30 hydrogen atoms. Please provide steps to undertand each labeling. Please label in the image, so it fits explanation. I am still very unsure I undertand this.arrow_forwardDon't used Ai solutionarrow_forwardDon't used Ai solutionarrow_forward
- Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage LearningChemistry for Today: General, Organic, and Bioche...ChemistryISBN:9781305960060Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. HansenPublisher:Cengage Learning