Organic Chemistry: Principles and Mechanisms (Second Edition)
Organic Chemistry: Principles and Mechanisms (Second Edition)
2nd Edition
ISBN: 9780393663556
Author: Joel Karty
Publisher: W. W. Norton & Company
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Chapter 11, Problem 11.61P
Interpretation Introduction

Interpretation:

The structures of compounds J through N in the given reaction scheme are to be determined.

Concept introduction:

Vinyl chlorides are sufficiently electron rich and undergo an E2 elimination reaction when treated with an excess of a strong base such as soda amide. As the reaction medium is strongly basic, the anion of an alkyne is formed. In the second step of this reaction, water is added to yield an uncharged alkyne.

Terminal alkynes have a weakly acidic terminal hydrogen atom, which can be abstracted by a strong base such as soda amide. This will generate the anion of an alkyne. This anion act as a nucleophile and bonded to the least substituted carbon atom in the epoxide via SN2 reaction. This opens the epoxide ring and results in the alcohol with the original alkyne.

Alcohols undergo SN2 reactions with phosphorous halides to yield the corresponding halides. This reaction converts ROH into RBr.

Tetrafluoromethanesulfuric acid, also known as triflic acid, and 2, 2, 2-trifluoroethanol make a strong acid that can be used as a catalyst in the acid-catalyzed hydration reactions of alkynes. In this reaction, alkynes are converted into a ketone.

Alkyl halides, when treated with a strong nucleophile, undergo an SN2 reaction to yield products.

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Choose the Lewis structure for the compound below: H2CCHOCH2CH(CH3)2 HH H :d H H H C. Η H H HH H H H H. H H H HH H H H H H- H H H C-H H H HHHH
Each of the highlighted carbon atoms is connected to hydrogen atoms.
く Complete the reaction in the drawing area below by adding the major products to the right-hand side. If there won't be any products, because nothing will happen under these reaction conditions, check the box under the drawing area instead. Note: if the products contain one or more pairs of enantiomers, don't worry about drawing each enantiomer with dash and wedge bonds. Just draw one molecule to represent each pair of enantiomers, using line bonds at the chiral center. More... No reaction. Explanation Check O + G 1. Na O Me Click and drag to start drawing a structure. 2. H + 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility 000 Ar P

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Organic Chemistry: Principles and Mechanisms (Second Edition)

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