BIO TORQUES AND TUG-OF-WAR. In a study of the biomechanics of the tug-of-war, a 2.0-m-tall, 80.0-kg competitor in the middle of the line is considered to be a rigid body leaning back at an angle of 30.0° to the vertical. The competitor is pulling on a rope that is held horizontal a distance of 1.5 m from his feet (as measured along the line of the body). At the moment shown in the figure, the man is stationary and the tension in the rope in front of him is T 1 = 1160 N. Since there is friction between the rope and his hands, the tension in the rope behind him, T 2, is not equal to T 1 . His center of mass is halfway between his feet and the top of his head. The coefficient of static friction between his feet and the ground is 0.65. 11.92 What is tension T 2 in the rope behind him? (a) 590 N; (b) 650 N; (c) 860 N;(d) 1100 N.N.
BIO TORQUES AND TUG-OF-WAR. In a study of the biomechanics of the tug-of-war, a 2.0-m-tall, 80.0-kg competitor in the middle of the line is considered to be a rigid body leaning back at an angle of 30.0° to the vertical. The competitor is pulling on a rope that is held horizontal a distance of 1.5 m from his feet (as measured along the line of the body). At the moment shown in the figure, the man is stationary and the tension in the rope in front of him is T 1 = 1160 N. Since there is friction between the rope and his hands, the tension in the rope behind him, T 2, is not equal to T 1 . His center of mass is halfway between his feet and the top of his head. The coefficient of static friction between his feet and the ground is 0.65. 11.92 What is tension T 2 in the rope behind him? (a) 590 N; (b) 650 N; (c) 860 N;(d) 1100 N.N.
BIO TORQUES AND TUG-OF-WAR. In a study of the biomechanics of the tug-of-war, a 2.0-m-tall, 80.0-kg competitor in the middle of the line is considered to be a rigid body leaning back at an angle of 30.0° to the vertical. The competitor is pulling on a rope that is held horizontal a distance of 1.5 m from his feet (as measured along the line of the body). At the moment shown in the figure, the man is stationary and the tension in the rope in front of him is T1 = 1160 N. Since there is friction between the rope and his hands, the tension in the rope behind him, T2, is not equal to T1. His center of mass is halfway between his feet and the top of his head. The coefficient of static friction between his feet and the ground is 0.65.
11.92 What is tension T2 in the rope behind him? (a) 590 N; (b) 650 N; (c) 860 N;(d) 1100 N.N.
Need help on the following questions on biomechanics. (Please refer to images below)A gymnast weighing 68 kg attempts a handstand using only one arm. He plants his handat an angle resulting in the reaction force shown.A) Find the resultant force (acting on the Center of Mass)B) Find the resultant moment (acting on the Center of Mass)C) Draw the resultant force and moment about the center of mass on the figure below. Will the gymnast rotate, translate, or both? And in which direction?
Please help me on the following question (Please refer to image below)An Olympic lifter (m = 103kg) is holding a lift with a mass of 350 kg. The barexerts a purely vertical force that is equally distributed between both hands. Each arm has amass of 9 kg, are 0.8m long and form a 40° angle with the horizontal. The CoM for each armis 0.5 m from hand. Assuming the lifter is facing us in the diagram below, his right deltoidinserts 14cm from the shoulder at an angle of 13° counter-clockwise from the humerus.A) You are interested in calculating the force in the right deltoid. Draw a free body diagramof the right arm including the external forces, joint reaction forces, a coordinate system andstate your assumptions.B) Find the force exerted by the right deltoidC) Find the shoulder joint contact force. Report your answer using the magnitude and directionof the shoulder force vector.
Chapter 11 Solutions
University Physics with Modern Physics (14th Edition)
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