Explanation Water skier lean backward to come back to the equilibrium. When the water skier come to backward the torque produce by the ski pull line and torque produce by mass become equal. The mass of skier is m the tension produce in the opposite direction is T when the skier is placed in the water at the angle θ then a normal reaction is act on the skier end vertically upward N and force F act in the right direction. The free body diagram is given below. Figure I Apply the equilibrium condition in the vertical direction. N − m g = 0 N = m g N is the normal force m is the mass of the skier g is the acceleration due to gravity Apply the equilibrium condition in the horizontal direction. f = T f is the frictional force between the skier feet and the water T is the tension in the rope held by the skier . All the forces are in equilibrium but if the skier is moving with constant velocity without rotate in the same direction then the torque must be equal to zero. ∑ τ = 0 Let l is the distance at which the tension is produce and ( l − x ) is the distance at which the weight of skier act

University Physics with Modern Physics (14th Edition)

14th Edition

ISBN: 9780321973610

Author: Hugh D. Young, Roger A. Freedman

Publisher: PEARSON

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Chapter 11, Problem 11.11DQ

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The reason for a water skier moving with constant velocity lean backward and the distance she must lean.

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Chapter 11 Solutions

University Physics with Modern Physics (14th Edition)

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The reason for a water skier moving with constant velocity lean backward and the distance she must lean.

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The reason for a water skier moving with constant velocity lean backward and the distance she must lean.

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Chapter 11 Solutions