a) Interpretation: The IUPAC name of the alkyl halide is to be given. Concept introduction: The longest continuous carbon chain in the molecule is chosen. The chain is numbered from the end which gives lowest number to the substituent either halo or alkyl group present. If different halogens are present they are numbered and listed in the alphabetical order while writing the name. If same two alternatives exist for different substituents, then the chain is numbered from the end that gives lowest number to the substituent that has alphabetical preference. To give: The IUPAC name of the alkyl halide shown.

Question

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Answer 1

Question

Chapter 10.SE, Problem 14VC

Interpretation Introduction

a)

Interpretation:

The IUPAC name of the alkyl halide is to be given.

Concept introduction:

The longest continuous carbon chain in the molecule is chosen. The chain is numbered from the end which gives lowest number to the substituent either halo or alkyl group present. If different halogens are present they are numbered and listed in the alphabetical order while writing the name. If same two alternatives exist for different substituents, then the chain is numbered from the end that gives lowest number to the substituent that has alphabetical preference.

To give:

The IUPAC name of the alkyl halide shown.

Expert Solution

Answer to Problem 14VC

The alkyl halide given is

Organic Chemistry, Chapter 10.SE, Problem 14VC , additional homework tip 2

Its IUPAC name is cis- 1- chloro-3-methylcyclohexane.

Explanation of Solution

The compound has a cyclohexane ring with a Cl atom on C₁ and a methyl on C₃ both at equatorial positions. Hence its name is cis- 1- chloro-3-methylcyclohexane.

Conclusion

The IUPAC name of the alkyl halide shown is cis- 1- chloro-3-methylcyclohexane.

Interpretation Introduction

b)

Interpretation:

The IUPAC name of the alkyl halide is to be given.

Concept introduction:

The longest continuous carbon chain in the molecule is chosen. The chain is numbered from the end which gives lowest number to the substituent either halo or alkyl group present. If different halogens are present they are numbered and listed in the alphabetical order while writing the name. If same two alternatives exist for different substituents, then the chain is numbered from the end that gives lowest number to the substituent that has alphabetical preference.

To give:

The IUPAC name of the alkyl halide shown.

Expert Solution

Answer to Problem 14VC

The alkyl halide given is

Organic Chemistry, Chapter 10.SE, Problem 14VC , additional homework tip 4

Its IUPAC name is 4-chloro-2-methyl-2-heptene.

Explanation of Solution

The compound has a seven carbon straight chain with a double bond between C₂ & C₃, a Cl atom on C₄ and a methyl on C₃. Hence its name is 4-chloro-2-methyl-2-heptene.

Conclusion

The IUPAC name of the alkyl halide shown is 4-chloro-2-methyl-2-heptene.

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b. H3C CH3 1. 2. H3O+ H3C MgBr H3C

Predict the major products of this reaction: excess H+ NaOH ? A Note that the first reactant is used in excess, that is, there is much more of the first reactant than the second. If there won't be any products, just check the box under the drawing area instead. Explanation Check Click and drag to start drawing a structure. © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use Priv

1. For each of the reaction "railroads" below, you are either asked to give the structure(s) of the starting material(s) or product(s), or provide reagents/conditions to accomplish the transformation, as indicated by the boxes. a. NaOMe H+ .CO,H HO₂C MeOH (excess) MeOH H3C Br يع CH3 1. LiAlH4 2. H3O+ 3. PBг3 H3C 1. Et-Li 2. H3O+ -CO₂Me -CO₂Me OH CH3 CH3 ল CH3

Answer 2

Question

Chapter 10.SE, Problem 14VC

Interpretation Introduction

a)

Interpretation:

The IUPAC name of the alkyl halide is to be given.

Concept introduction:

The longest continuous carbon chain in the molecule is chosen. The chain is numbered from the end which gives lowest number to the substituent either halo or alkyl group present. If different halogens are present they are numbered and listed in the alphabetical order while writing the name. If same two alternatives exist for different substituents, then the chain is numbered from the end that gives lowest number to the substituent that has alphabetical preference.

To give:

The IUPAC name of the alkyl halide shown.

Expert Solution

Answer to Problem 14VC

The alkyl halide given is

Organic Chemistry, Chapter 10.SE, Problem 14VC , additional homework tip 2

Its IUPAC name is cis- 1- chloro-3-methylcyclohexane.

Explanation of Solution

The compound has a cyclohexane ring with a Cl atom on C₁ and a methyl on C₃ both at equatorial positions. Hence its name is cis- 1- chloro-3-methylcyclohexane.

Conclusion

The IUPAC name of the alkyl halide shown is cis- 1- chloro-3-methylcyclohexane.

Interpretation Introduction

b)

Interpretation:

The IUPAC name of the alkyl halide is to be given.

Concept introduction:

The longest continuous carbon chain in the molecule is chosen. The chain is numbered from the end which gives lowest number to the substituent either halo or alkyl group present. If different halogens are present they are numbered and listed in the alphabetical order while writing the name. If same two alternatives exist for different substituents, then the chain is numbered from the end that gives lowest number to the substituent that has alphabetical preference.

To give:

The IUPAC name of the alkyl halide shown.

Expert Solution

Answer to Problem 14VC

The alkyl halide given is

Organic Chemistry, Chapter 10.SE, Problem 14VC , additional homework tip 4

Its IUPAC name is 4-chloro-2-methyl-2-heptene.

Explanation of Solution

The compound has a seven carbon straight chain with a double bond between C₂ & C₃, a Cl atom on C₄ and a methyl on C₃. Hence its name is 4-chloro-2-methyl-2-heptene.

Conclusion

The IUPAC name of the alkyl halide shown is 4-chloro-2-methyl-2-heptene.

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Answer 3

Question

Chapter 10.SE, Problem 14VC

Interpretation Introduction

a)

Interpretation:

The IUPAC name of the alkyl halide is to be given.

Concept introduction:

The longest continuous carbon chain in the molecule is chosen. The chain is numbered from the end which gives lowest number to the substituent either halo or alkyl group present. If different halogens are present they are numbered and listed in the alphabetical order while writing the name. If same two alternatives exist for different substituents, then the chain is numbered from the end that gives lowest number to the substituent that has alphabetical preference.

To give:

The IUPAC name of the alkyl halide shown.

Expert Solution

Answer to Problem 14VC

The alkyl halide given is

Organic Chemistry, Chapter 10.SE, Problem 14VC , additional homework tip 2

Its IUPAC name is cis- 1- chloro-3-methylcyclohexane.

Explanation of Solution

The compound has a cyclohexane ring with a Cl atom on C₁ and a methyl on C₃ both at equatorial positions. Hence its name is cis- 1- chloro-3-methylcyclohexane.

Conclusion

The IUPAC name of the alkyl halide shown is cis- 1- chloro-3-methylcyclohexane.

Interpretation Introduction

b)

Interpretation:

The IUPAC name of the alkyl halide is to be given.

Concept introduction:

The longest continuous carbon chain in the molecule is chosen. The chain is numbered from the end which gives lowest number to the substituent either halo or alkyl group present. If different halogens are present they are numbered and listed in the alphabetical order while writing the name. If same two alternatives exist for different substituents, then the chain is numbered from the end that gives lowest number to the substituent that has alphabetical preference.

To give:

The IUPAC name of the alkyl halide shown.

Expert Solution

Answer to Problem 14VC

The alkyl halide given is

Organic Chemistry, Chapter 10.SE, Problem 14VC , additional homework tip 4

Its IUPAC name is 4-chloro-2-methyl-2-heptene.

Explanation of Solution

The compound has a seven carbon straight chain with a double bond between C₂ & C₃, a Cl atom on C₄ and a methyl on C₃. Hence its name is 4-chloro-2-methyl-2-heptene.

Conclusion

The IUPAC name of the alkyl halide shown is 4-chloro-2-methyl-2-heptene.

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Answer 4

Question

Chapter 10.SE, Problem 14VC

Interpretation Introduction

a)

Interpretation:

The IUPAC name of the alkyl halide is to be given.

Concept introduction:

The longest continuous carbon chain in the molecule is chosen. The chain is numbered from the end which gives lowest number to the substituent either halo or alkyl group present. If different halogens are present they are numbered and listed in the alphabetical order while writing the name. If same two alternatives exist for different substituents, then the chain is numbered from the end that gives lowest number to the substituent that has alphabetical preference.

To give:

The IUPAC name of the alkyl halide shown.

Expert Solution

Answer to Problem 14VC

The alkyl halide given is

Organic Chemistry, Chapter 10.SE, Problem 14VC , additional homework tip 2

Its IUPAC name is cis- 1- chloro-3-methylcyclohexane.

Explanation of Solution

The compound has a cyclohexane ring with a Cl atom on C₁ and a methyl on C₃ both at equatorial positions. Hence its name is cis- 1- chloro-3-methylcyclohexane.

Conclusion

The IUPAC name of the alkyl halide shown is cis- 1- chloro-3-methylcyclohexane.

Interpretation Introduction

b)

Interpretation:

The IUPAC name of the alkyl halide is to be given.

Concept introduction:

The longest continuous carbon chain in the molecule is chosen. The chain is numbered from the end which gives lowest number to the substituent either halo or alkyl group present. If different halogens are present they are numbered and listed in the alphabetical order while writing the name. If same two alternatives exist for different substituents, then the chain is numbered from the end that gives lowest number to the substituent that has alphabetical preference.

To give:

The IUPAC name of the alkyl halide shown.

Expert Solution

Answer to Problem 14VC

The alkyl halide given is

Organic Chemistry, Chapter 10.SE, Problem 14VC , additional homework tip 4

Its IUPAC name is 4-chloro-2-methyl-2-heptene.

Explanation of Solution

The compound has a seven carbon straight chain with a double bond between C₂ & C₃, a Cl atom on C₄ and a methyl on C₃. Hence its name is 4-chloro-2-methyl-2-heptene.

Conclusion

The IUPAC name of the alkyl halide shown is 4-chloro-2-methyl-2-heptene.

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Answer 5

Chapter 10.SE, Problem 14VC

Interpretation Introduction

a)

Interpretation:

The IUPAC name of the alkyl halide is to be given.

Concept introduction:

The longest continuous carbon chain in the molecule is chosen. The chain is numbered from the end which gives lowest number to the substituent either halo or alkyl group present. If different halogens are present they are numbered and listed in the alphabetical order while writing the name. If same two alternatives exist for different substituents, then the chain is numbered from the end that gives lowest number to the substituent that has alphabetical preference.

To give:

The IUPAC name of the alkyl halide shown.

Expert Solution

Answer to Problem 14VC

The alkyl halide given is

Organic Chemistry, Chapter 10.SE, Problem 14VC , additional homework tip 2

Its IUPAC name is cis- 1- chloro-3-methylcyclohexane.

Explanation of Solution

The compound has a cyclohexane ring with a Cl atom on C₁ and a methyl on C₃ both at equatorial positions. Hence its name is cis- 1- chloro-3-methylcyclohexane.

Conclusion

The IUPAC name of the alkyl halide shown is cis- 1- chloro-3-methylcyclohexane.

Interpretation Introduction

b)

Interpretation:

The IUPAC name of the alkyl halide is to be given.

Concept introduction:

The longest continuous carbon chain in the molecule is chosen. The chain is numbered from the end which gives lowest number to the substituent either halo or alkyl group present. If different halogens are present they are numbered and listed in the alphabetical order while writing the name. If same two alternatives exist for different substituents, then the chain is numbered from the end that gives lowest number to the substituent that has alphabetical preference.

To give:

The IUPAC name of the alkyl halide shown.

Expert Solution

Answer to Problem 14VC

The alkyl halide given is

Organic Chemistry, Chapter 10.SE, Problem 14VC , additional homework tip 4

Its IUPAC name is 4-chloro-2-methyl-2-heptene.

Explanation of Solution

The compound has a seven carbon straight chain with a double bond between C₂ & C₃, a Cl atom on C₄ and a methyl on C₃. Hence its name is 4-chloro-2-methyl-2-heptene.

Conclusion

The IUPAC name of the alkyl halide shown is 4-chloro-2-methyl-2-heptene.

Answer 6

Chapter 10.SE, Problem 14VC

Interpretation Introduction

a)

Interpretation:

The IUPAC name of the alkyl halide is to be given.

Concept introduction:

The longest continuous carbon chain in the molecule is chosen. The chain is numbered from the end which gives lowest number to the substituent either halo or alkyl group present. If different halogens are present they are numbered and listed in the alphabetical order while writing the name. If same two alternatives exist for different substituents, then the chain is numbered from the end that gives lowest number to the substituent that has alphabetical preference.

To give:

The IUPAC name of the alkyl halide shown.

Expert Solution

Answer to Problem 14VC

The alkyl halide given is

Organic Chemistry, Chapter 10.SE, Problem 14VC , additional homework tip 2

Its IUPAC name is cis- 1- chloro-3-methylcyclohexane.

Explanation of Solution

The compound has a cyclohexane ring with a Cl atom on C₁ and a methyl on C₃ both at equatorial positions. Hence its name is cis- 1- chloro-3-methylcyclohexane.

Conclusion

The IUPAC name of the alkyl halide shown is cis- 1- chloro-3-methylcyclohexane.

Answer 7

Chapter 10.SE, Problem 14VC

Interpretation Introduction

a)

Interpretation:

The IUPAC name of the alkyl halide is to be given.

Concept introduction:

The longest continuous carbon chain in the molecule is chosen. The chain is numbered from the end which gives lowest number to the substituent either halo or alkyl group present. If different halogens are present they are numbered and listed in the alphabetical order while writing the name. If same two alternatives exist for different substituents, then the chain is numbered from the end that gives lowest number to the substituent that has alphabetical preference.

To give:

The IUPAC name of the alkyl halide shown.

Answer 8

Expert Solution

Answer to Problem 14VC

The alkyl halide given is

Organic Chemistry, Chapter 10.SE, Problem 14VC , additional homework tip 2

Its IUPAC name is cis- 1- chloro-3-methylcyclohexane.

Answer 9

Expert Solution

Answer 10

Expert Solution

Answer 11

Expert Solution

Answer 12

Explanation of Solution

The compound has a cyclohexane ring with a Cl atom on C₁ and a methyl on C₃ both at equatorial positions. Hence its name is cis- 1- chloro-3-methylcyclohexane.

Answer 13

Conclusion

The IUPAC name of the alkyl halide shown is cis- 1- chloro-3-methylcyclohexane.

Answer 14

Interpretation Introduction

b)

Interpretation:

The IUPAC name of the alkyl halide is to be given.

Concept introduction:

The longest continuous carbon chain in the molecule is chosen. The chain is numbered from the end which gives lowest number to the substituent either halo or alkyl group present. If different halogens are present they are numbered and listed in the alphabetical order while writing the name. If same two alternatives exist for different substituents, then the chain is numbered from the end that gives lowest number to the substituent that has alphabetical preference.

To give:

The IUPAC name of the alkyl halide shown.

Expert Solution

Answer to Problem 14VC

The alkyl halide given is

Organic Chemistry, Chapter 10.SE, Problem 14VC , additional homework tip 4

Its IUPAC name is 4-chloro-2-methyl-2-heptene.

Explanation of Solution

The compound has a seven carbon straight chain with a double bond between C₂ & C₃, a Cl atom on C₄ and a methyl on C₃. Hence its name is 4-chloro-2-methyl-2-heptene.

Conclusion

The IUPAC name of the alkyl halide shown is 4-chloro-2-methyl-2-heptene.

Answer 15

Interpretation Introduction

b)

Interpretation:

The IUPAC name of the alkyl halide is to be given.

Concept introduction:

The longest continuous carbon chain in the molecule is chosen. The chain is numbered from the end which gives lowest number to the substituent either halo or alkyl group present. If different halogens are present they are numbered and listed in the alphabetical order while writing the name. If same two alternatives exist for different substituents, then the chain is numbered from the end that gives lowest number to the substituent that has alphabetical preference.

To give:

The IUPAC name of the alkyl halide shown.

Answer 16

Expert Solution

Answer to Problem 14VC

The alkyl halide given is

Organic Chemistry, Chapter 10.SE, Problem 14VC , additional homework tip 4

Its IUPAC name is 4-chloro-2-methyl-2-heptene.

Answer 17

Expert Solution

Answer 18

Expert Solution

Answer 19

Expert Solution

Answer 20

Explanation of Solution

The compound has a seven carbon straight chain with a double bond between C₂ & C₃, a Cl atom on C₄ and a methyl on C₃. Hence its name is 4-chloro-2-methyl-2-heptene.

Answer 21

Conclusion

The IUPAC name of the alkyl halide shown is 4-chloro-2-methyl-2-heptene.

Answer 22

Ch. 10.1 - Prob. 1P Ch. 10.1 - Draw structures corresponding to the following...Ch. 10.2 - Prob. 3P Ch. 10.2 - Taking the relative reactivities of 1Â°, 2Â°, and...Ch. 10.4 - Prob. 5P Ch. 10.4 - The major product of the reaction of...Ch. 10.4 - Prob. 7P Ch. 10.5 - Prob. 8P Ch. 10.6 - Prob. 9P Ch. 10.6 - How might you replace a halogen substituent by a...

Concept explainers

Answer to Problem 14VC

Explanation of Solution

Answer to Problem 14VC

Explanation of Solution

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