
Concept explainers
(a)
Interpretation:
The given alkyl halide forms whether primarily substitution products, only elimination products, both substitution and elimination products, or no products when they react under the given conditions have to be explained.
Concept Introduction:
Elimination Reaction: It is just reverse reaction of addition where substituent from the given molecule is removed via E1 (the reaction depends only on the substrate involved in the reaction) or E2 (the reaction depends on both of the substituents in the reaction) mechanism. Elimination reaction of an alkyl halide results in the formation of an
SN1 Reaction: it is a nucleophilic substitution reaction in which the rate determining step depends on one reactant. First step is the formation of more stable carbocation which is followed by the attack of nucleophile. Formation of more stable carbocation and the leaving group present in the substrate plays very important role in the reactivity of
SN2 reactions take place in primary and secondary
Tertiary alkyl halides undergo both E1 and E2 reactions whereas only E2 reactions take place in primary and secondary alkyl halides.
Carbocation: it is carbon ion that bears a positive charge on it. The increasing stability order of carbocation is as follows,
Primary carbocation < secondary carbocation < tertiary carbocation
Nucleophile: donates pair of electrons to positively charged substrate resulting in the formation of
(b)
Interpretation:
The given alkyl halide forms whether primarily substitution products, only elimination products, either substitution and elimination products, or no products when they react under the given conditions have to be explained.
Concept Introduction:
Elimination Reaction: It is just reverse reaction of addition where substituent from the given molecule is removed via E1 (the reaction depends only on the substrate involved in the reaction) or E2 (the reaction depends on both of the substituents in the reaction) mechanism. Elimination reaction of an alkyl halide results in the formation of an alkene.
SN1 Reaction: it is a nucleophilic substitution reaction in which the rate determining step depends on one reactant. First step is the formation of more stable carbocation which is followed by the attack of nucleophile. Formation of more stable carbocation and the leaving group present in the substrate plays very important role in the reactivity of
SN2 reactions take place in primary and secondary alkyl halides whereas SN1 reactions takes place only in tertiary alky halide.
Tertiary alkyl halides undergo both E1 and E2 reactions whereas only E2 reactions take place in primary and secondary alkyl halides.
Carbocation: it is carbon ion that bears a positive charge on it. The increasing stability order of carbocation is as follows,
Primary carbocation < secondary carbocation < tertiary carbocation
Nucleophile: donates pair of electrons to positively charged substrate resulting in the formation of chemical bond.

Want to see the full answer?
Check out a sample textbook solution
Chapter 10 Solutions
Organic Chemistry
- Calculate the ionization energy of He+ and Li²+ ions in their ground states. Thannnxxxxx sirrr Ahehehehehejh27278283-4;*; shebehebbw $+$;$-;$-28283773838 hahhehdvaarrow_forwardPlleeaasseee solllveeee question 3 andd thankss sirr, don't solve it by AI plleeaasseee don't use AIarrow_forwardCalculate the chemical shifts in 13C and 1H NMR for 4-chloropropiophenone ? Write structure and label hydrogens and carbonsarrow_forward
- 4. Read paragraph 4.15 from your textbook, use your calculated lattice energy values for CuO, CuCO3 and Cu(OH)2 an explain thermal decomposition reaction of malachite: Cu2CO3(OH)2 →2CuO + H2O + CO2 (3 points)arrow_forwardPlease sirrr soollveee these parts pleaseeee and thank youuuuuarrow_forwardIII O Organic Chemistry Using wedges and dashes in skeletal structures Draw a skeletal ("line") structure for each of the molecules below. Be sure your structures show the important difference between the molecules. key O O O O O CHON Cl jiii iiiiiiii You can drag the slider to rotate the molecules. Explanation Check Click and drag to start drawing a structure. Q Search X G ©2025 McGraw Hill LLC. All Rights Reserved. Terms of Use F 3 W C 3/5arrow_forward
- 3. Use Kapustinskii's equation and data from Table 4.10 in your textbook to calculate lattice energies of Cu(OH)2 and CuCO3 (4 points)arrow_forward2. Copper (II) oxide crystalizes in monoclinic unit cell (included below; blue spheres 2+ represent Cu²+, red - O²-). Use Kapustinski's equation (4.5) to calculate lattice energy for CuO. You will need some data from Resource section of your textbook (p.901). (4 points) CuOarrow_forwardWhat is the IUPAC name of the following compound? OH (2S, 4R)-4-chloropentan-2-ol O (2R, 4R)-4-chloropentan-2-ol O (2R, 4S)-4-chloropentan-2-ol O(2S, 4S)-4-chloropentan-2-olarrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY





