Chapter 10.1, Problem 1PPB

Interpretation Introduction

Interpretation:

The height of column of water supported by the pressure of $\text{0}\text{.921 atm}$ is to be calculated.

Concept Introduction:

The pressure exerted by a column of fluid is calculated as follows:

$P=hdg$

Here, d is the density of the fluid in ${\text{kg/m}}^{\text{3}}$, g is the gravitational constant, and h is the height of the column in meters.

The height of the column can be calculated by rearranging this formula.

The relationship between atmosphere $(atm)$ and Pascal $(Pa)$ can be expressed as:

$1\text{atm}\text{=}101,325\text{ Pa}$

To convert $(atm)$ to $(Pa)$, the conversion factor is $\frac{101,325\text{ Pa}}{1\text{ atm}}$

The relationship between atmosphere $(kg)$ and Pascal $(g)$ can be expressed as:

$1\text{kg}\text{=}1000\text{g}$

To convert $(g)$ to $(kg)$, the conversion factor is $\frac{1\text{kg}}{1000\text{ g}}$

The relationship between atmosphere $(m)$ and Pascal $(cm)$ can be expressed as:

$1\text{m}\text{=}100\text{cm}$

To convert $(cm)$ to $(m)$, the conversion factor is $\frac{1\text{m}}{100\text{ cm}}$