College Physics: A Strategic Approach (3rd Edition)
3rd Edition
ISBN: 9780321879721
Author: Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher: PEARSON
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Chapter 10, Problem 27P
A 25 kg child slides down a playground slide at a constant speed. The slide has a height of 3.0 m and is 7.0 m long. Using the law of conservation of energy, find the magnitude of the kinetic friction force acting on the child.
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An 5.00 Kg object,initially at rest on a horizontal surface, was pushed using a force oriented 30.0 degrees above the horizontal and having a magnitude of 43.0 N. The object was pushed a distance of 3.00 m. The coefficient of kinetic friction between the surface and the object is 0.400. What is the change in kinetic energy?
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to t = 5.0 s?
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A 6.00 kg block is pulled up a frictionless inclined plane by a 90.0 N force that is parallel to the slope of the incline, starting from rest. The normal force on the block from the plane has a magnitude of 18.5 N. What is the block’s speed when its displacement up the ramp is 4.00 m?
Chapter 10 Solutions
College Physics: A Strategic Approach (3rd Edition)
Ch. 10 - The brake shoes of your car are made of a material...Ch. 10 - When you pound a nail with a hammer, the nail gets...Ch. 10 - For Questions 3 through 1 0, give a specific...Ch. 10 - For Questions 3 through 1 0, give a specific...Ch. 10 - For Questions 3 through 10, give a specific...Ch. 10 - For Questions 3 through 10, give a specific...Ch. 10 - For Questions 3 through 1 0, give a specific...Ch. 10 - For Questions 3 through 1 0, give a specific...Ch. 10 - For Questions 3 through 1 0, give a specific...Ch. 10 - For Questions 3 through 1 0, give a specific...
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When...Ch. 10 - Prob. 37PCh. 10 - Prob. 38PCh. 10 - In the winter activity of tubing, riders slide...Ch. 10 - A cyclist is coasting at 12 m/s when she starts...Ch. 10 - A 50 g marble moving at 2.0 m/s strikes a 20 g...Ch. 10 - Ball 1, with a mass of 100 g and traveling at 10...Ch. 10 - Prob. 43PCh. 10 - Two balls undergo a perfectly elastic head-on...Ch. 10 - Prob. 45PCh. 10 - Prob. 46PCh. 10 - A 1000 kg sports car accelerates from 0 to 30m/sin...Ch. 10 - In just 0.30 s, you compress a spring (spring...Ch. 10 - An elite Tour de France cyclist can maintain an...Ch. 10 - A 710 kg car drives at a constant speed of 23 m/s....Ch. 10 - An elevator weighing 2500 N ascends at a constant...Ch. 10 - How much work does Scott do to push a 80 kg sofa...Ch. 10 - A 550 kg elevator accelerates upward at 1.2 m/s2...Ch. 10 - Prob. 54GPCh. 10 - Prob. 55GPCh. 10 - Prob. 56GPCh. 10 - You are driving your 1500 kg car at 20 m/s down a...Ch. 10 - A 20 kg child is on a swing that hangs from...Ch. 10 - Prob. 59GPCh. 10 - A cannon tilted up at a 30 angle fires a cannon...Ch. 10 - The sledder shown in Figure P10.61 starts from the...Ch. 10 - A 50 g ice cube can slide without friction up and...Ch. 10 - The maximum energy a bone can absorb without...Ch. 10 - In an amusement park water slide, people slide...Ch. 10 - Boxes A and B in Figure P10.69 have masses of 12.0...Ch. 10 - What would be the speed of the boxes in Problem 69...Ch. 10 - A 20 g ball is fired horizontally with initial...Ch. 10 - Two coupled boxcars are rolling along at 2.5 m/s...Ch. 10 - A fish scale, consisting of a spring with spring...Ch. 10 - A 70 kg human sprinter can accelerate from rest to...Ch. 10 - A 50 g ball of clay traveling at 6.5 m/s hits and...Ch. 10 - Prob. 78GPCh. 10 - The mass of an elevator and its occupants is 1200...Ch. 10 - Prob. 80GPCh. 10 - Tennis Ball Testing A tennis ball bouncing on a...Ch. 10 - Tennis Ball Testing A tennis ball bouncing on a...Ch. 10 - Tennis Ball Testing A tennis ball bouncing on a...Ch. 10 - Prob. 84MSPPCh. 10 - Tennis Ball Testing A tennis ball bouncing on a...Ch. 10 - Work and Power in Cycling When you ride a bicycle...Ch. 10 - Work and Power in Cycling When you ride a bicycle...Ch. 10 - Work and Power in Cycling When you ride a bicycle...Ch. 10 - Work and Power in Cycling When you ride a bicycle...Ch. 10 - Work and Power in Cycling When you ride a bicycle...
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- Estimate the kinetic energy of the following: a. An ant walking across the kitchen floor b. A baseball thrown by a professional pitcher c. A car on the highway d. A large truck on the highwayarrow_forwardA large cruise ship of mass 6.50 107 kg has a speed of 12.0 m/s at some instant. (a) What is the ships kinetic energy at this time? (b) How much work is required to stop it? (c) What is the magnitude of the constant force required to stop it as it undergoes a displacement of 2.50 km?arrow_forwardA particle moves in the xy plane (Fig. P9.30) from the origin to a point having coordinates x = 7.00 m and y = 4.00 m under the influence of a force given by F=3y2+x. a. What is the work done on the particle by the force F if it moves along path 1 (shown in red)? b. What is the work done on the particle by the force F if it moves along path 2 (shown in blue)? c. What is the work done on the particle by the force F if it moves along path 3 (shown in green)? d. Is the force F conservative or nonconservative? Explain. FIGURE P9.30 In each case, the work is found using the integral of Fdr along the path (Equation 9.21). W=rtrfFdr=rtrf(Fxdx+Fydy+Fzdz) (a) The work done along path 1, we first need to integrate along dr=dxi from (0,0) to (7,0) and then along dr=dyj from (7,0) to (7,4): W1=x=0;y=0x=7;y=0(3y2i+xj)(dxi)+x=7;y=0x=7;y=4(3y2i+xj)(dyj) Performing the dot products, we get W1=x=0;y=0x=7;y=03y2dx+x=7;y=0x=7;y=4xdy Along the first part of this path, y = 0 therefore the first integral equals zero. For the second integral, x is constant and can be pulled out of the integral, and we can evaluate dy. W1=0+x=7;y=0x=7;y=4xdy=xy|x=7;y=0x=7;y=4=28J (b) The work done along path 2 is along dr=dyj from (0,0) to (0,4) and then along dr=dxi from (0,4) to (7,4): W2=x=0;y=0x=0;y=4(3y2i+xj)(dyj)+x=0;y=4x=7;y=4(3y2i+xj)(dyi) Performing the dot product, we get: W2=x=0;y=0x=0;y=4xdy+x=0;y=4x=7;y=43y2dx Along the first part of this path, x = 0. Therefore, the first integral equals zero. For the second integral, y is constant and can be pulled out of the integral, and we can evaluate dx. W2=0+3y2x|x=0;y=4x=7;y=4=336J (c) To find the work along the third path, we first write the expression for the work integral. W=rtrfFdr=rtrf(Fxdx+Fydy+Fzdz)W=rtrf(3y2dx+xdy)(1) At first glance, this appears quite simple, but we cant integrate xdy=xy like we might have above because the value of x changes as we vary y (i.e., x is a function of y.) [In parts (a) and (b), on a straight horizontal or vertical line, only x or y changes]. One approach is to parameterize both x and y as a function of another variable, say t, and write each integral in terms of only x or y. Constraining dr to be along the desired line, we can relate dx and dy: tan=dydxdy=tandxanddx=dytan(2) Now, use equation (2) in (1) to express each integral in terms of only one variable. W=x=0;y=0x=7;y=43y2dx+x=0;y=0x=7;y=4xdyW=y=0y=43y2dytan+x=0x=7xtandx We can determine the tangent of the angle, which is constant (the angle is the angle of the line with respect to the horizontal). tan=4.007.00=0.570 Insert the value of the tangent and solve the integrals. W=30.570y33|y=0y=4+0.570x22|x=0x=7W=112+14=126J (d) Since the work done is not path-independent, this is non-conservative force. Figure P9.30ANSarrow_forward
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