(a) Interpretation: The wavelength of light corresponding to 1.00 × 10 − 32 J energy is to be stated. The comparison of this wavelength to the diameter of the Earth, which is 1.27 × 10 7 m , is to be shown. Concept introduction: The energy for particle in a box is given by the expression as follows. E = n 2 h 2 8 m a 2 Where, • E is the energy of the particle • n is the number of energy level • h is Planck’s constant • m is the mass of the particle • a is the width of the box The expression of the energy for particle in a box involves n which shows that the energy is quantized for a particle in a box.
(a) Interpretation: The wavelength of light corresponding to 1.00 × 10 − 32 J energy is to be stated. The comparison of this wavelength to the diameter of the Earth, which is 1.27 × 10 7 m , is to be shown. Concept introduction: The energy for particle in a box is given by the expression as follows. E = n 2 h 2 8 m a 2 Where, • E is the energy of the particle • n is the number of energy level • h is Planck’s constant • m is the mass of the particle • a is the width of the box The expression of the energy for particle in a box involves n which shows that the energy is quantized for a particle in a box.
Solution Summary: The author explains that the energy for particle in a box is given by the expression as follows.
The wavelength of light corresponding to 1.00×10−32J energy is to be stated. The comparison of this wavelength to the diameter of the Earth, which is 1.27×107m, is to be shown.
Concept introduction:
The energy for particle in a box is given by the expression as follows.
E=n2h28ma2
Where,
• E is the energy of the particle
• n is the number of energy level
• h is Planck’s constant
• m is the mass of the particle
• a is the width of the box
The expression of the energy for particle in a box involves n which shows that the energy is quantized for a particle in a box.
Interpretation Introduction
(b)
Interpretation:
The width of a box that an electron needs to be in, to possess 1.00×10−32J energy is to be calculated.
Concept introduction:
The energy for particle in a box is given by the expression as follows.
E=n2h28ma2
Where,
• E is the energy of the particle
• n is the number of energy levels
• h is Planck’s constant
• m is the mass of the particle
• a is the width of the box
The expression of the energy for particle in a box involves n which shows that the energy is quantized for a particle in a box.
K
Draw the starting structure that would lead to the major
product shown under the provided conditions.
Drawing
1. NaNH2
2. PhCH2Br
4 57°F
Sunny
Q Search
7
Draw the starting alkyl bromide that would produce this alkyne
under these conditions.
F
Drawing
1. NaNH2, A
2. H3O+
£
4 Temps to rise
Tomorrow
Q Search
H2
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