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(a)
Interpretation:
The substance that has the smallest dipole-dipole forces has to be given.
Concept Introduction:
Intermolecular forces:
Intermolecular forces are like cohesive forces, acting between the molecules. The overall stability of a compound depends on how strong the molecules are held together. Intermolecular force is concerned about the overall stability of a substance. A stable substance has stronger intermolecular forces.
Dipole-dipole forces:
A covalent bond is formed by mutual sharing of electrons between atoms. The two distinct types of covalent compounds are non-polar covalent and polar covalent compounds.
Atoms of the same element, particularly non-metals, bond which each other through covalent bond. There is no polarity between the atoms connected by the bond since the atoms have same electronegativity. Such type of compounds is non-polar covalent compounds. Hydrogen molecule is best example.
If atoms of slightly different electronegativity are covalently bonded, polarity arises spontaneously in the molecule due to the slight electronegativity difference between the atoms. Such compounds are polar covalent compounds.
In each molecule of a polar covalent compound, the electron cloud is displaced from the atom of low electronegativity to the atom of relatively high electronegativity through the covalent bond. As a result a “dipole” – a species containing weak partial positive and negative charge due to the unsymmetrical distribution of bonding electrons between atoms, is formed. Each dipole orient itself in such a direction that its positive end lies in close proximity to the negative end of the other dipole. The interaction between the dipoles is called “dipole-dipole forces”.
(b)
Interpretation:
The substance that has the largest Hydrogen bond forces has to be given.
Concept Introduction:
Intermolecular forces:
Intermolecular forces are like cohesive forces, acting between the molecules. The overall stability of a compound depends on how strong the molecules are held together. Intermolecular force is concerned about the overall stability of a substance. A stable substance has stronger intermolecular forces.
Hydrogen bond forces:
Hydrogen bonding is formed in polar covalent compounds containing hydrogen and other high electronegativity like fluorine, oxygen or nitrogen. These atoms in a molecule partially bond to hydrogen of the other same molecule or within a molecule. This type of bonding is called hydrogen bonding and it is stronger than dipole-dipole forces. Hydrogen bonding has significant impact on stability, density and other properties of matter. Water is a best example of hydrogen bonding, in which each oxygen atom of a water molecule forms hydrogen bond with hydrogen of another water molecule.
(c)
Interpretation:
The substance that has largest dispersion force has to be given.
Concept Introduction:
Intermolecular forces:
Intermolecular forces are like cohesive forces, acting between the molecules. The overall stability of a compound depends on how strong the molecules are held together. Intermolecular force is concerned about the overall stability of a substance. A stable substance has stronger intermolecular forces.
London dispersion force:
London dispersion forces exist in non-polar compounds whereas dipole-dipole forces exist in polar covalent compounds. Dipole-dipole force is stronger than London dispersion force. Both polar and non-polar covalent compounds have London dispersion forces. These forces are due to temporary dipoles and do not exist permanently. The molecules convert to dipoles instantly and disappear. This is due to the uneven distribution of electrons between their atoms occurs momentarily when the bonded electrons approach nucleus. Thus it is a weakest force.
Larger size molecules have lesser interaction between nuclei and electrons. Thus the electrons are free from nuclear force of attraction and easily form dipoles. Thus, larger the size of the molecules, higher is the strength of London dispersion force.
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Chapter 10 Solutions
General Chemistry: Atoms First
- Provide the IUPAC name of the following molecule. Don't forget to include the proper stereochemistry where appropriate.arrow_forward3. 2. 1. On the graph below, plot the volume of rain in milliliters versus its height in centimeters for the 400 mL beaker. Draw a straight line through the points and label it "400 mL beaker." Volume (mL) 400 350 300 250 200 150 750 mL Florence Volume Versus Height of Water 400 mL beaker 100 50 0 0 2 3 4 5 Height (cm) 6 7 8 9 10 Explain why the data points for the beaker lie roughly on a straight line. What kind of relationship is this? How do you know? (see page 276 text) the design of the beaker is a uniform cylinder the volume of liquid increases evenly with its height resulting in a linear relationship. What volume would you predict for 10.0 cm of water? Explain how you arrived at your answer. Use the data table and the graph to assist you in answering the question. 4. Plot the volume of rain in milliliters versus its height in centimeters for the 250 mL Florence flask on the same graph. Draw a best-fit curve through the points and label it "250 mL Florence flask." oke camearrow_forwardShow work. Don't give Ai generated solutionarrow_forward
- In the video, we looked at the absorbance of a certain substance and how it varies depending on what wavelength of light we are looking at. Below is a similar scan of a different substance. What color BEST describes how this substance will appear? Absorbance (AU) Violet Blue Green Orange 1.2 1.0- 0.8- 0.6- 0.4- 0.2 0.0 450 500 550 600 650 700 Wavelength (nm) violet indigo blue green yellow orange red Red O Cannot tell from this information In the above graph, what causes -450 nm wavelength of light to have a higher absorbance than light with a -550 nm wavelength? Check all that are true. The distance the light travels is different The different data points are for different substances The concentration is different at different times in the experiment Epsilon (molar absortivity) is different at different wavelengthsarrow_forward5. a. Data were collected for Trial 1 to determine the molar mass of a nonvolatile solid solute when dissolved in cyclo- hexane. Complete the table for the analysis (See Report Sheet). Record calculated values with the correct number of significant figures. B. Freezing Point of Cyclohexane plus Calculation Zone Unknown Solute 2. Mass of cyclohexane (g) 10.14 Part C.4 3. Mass of added solute (g) 0.255 C. Calculations 1. k; for cyclohexane (°C⚫ kg/mol) 20.0 2. Freezing point change, AT, (°C) 3.04 Part C.6 3. Mass of cyclohexane in solution (kg) 4. Moles of solute, total (mol) Show calculation. 5. Mass of solute in solution, total (g) 6. Molar mass of solute (g/mol) Show calculation.arrow_forwardDraw and name the R groups of all 20 amino acids.arrow_forward
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