Student Study Guide and Solutions Manual T/A Organic Chemistry
2nd Edition
ISBN: 9781118647950
Author: David R. Klein
Publisher: WILEY
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Question
Chapter 1, Problem 73CP
(a)
Interpretation Introduction
Interpretation:
To identify the hybridization state of boron atom, bond angle of
Concept introduction:
The atomic orbitals mix together to form a hybrid orbital which is suitable for forming bonds between the atoms to form a compound. This mixing of hybrid orbitals is known as hybridization. The hybridization determines the geometry of the particular atom in the compound. Shortly to say
trigonal pyramidal(if one lone pair of electron is present)
bent geometry (if two lone pair of electrons are present)
To identify: To identify the hybridization state of boron atom in given compound
(b)
Interpretation Introduction
Interpretation:
To identify the hybridization state of boron atom, bond angle of
Concept introduction:
The atomic orbitals mix together to form a hybrid orbital which is suitable for forming bonds between the atoms to form a compound. This mixing of hybrid orbitals is known as hybridization. The hybridization determines the geometry of the particular atom in the compound. Shortly to say
trigonal pyramidal(if one lone pair of electron is present)
bent geometry (if two lone pair of electrons are present)
To predict: To predict the bond angle of
(c)
Interpretation Introduction
Interpretation:
To identify the hybridization state of boron atom, bond angle of
Concept introduction:
The atomic orbitals mix together to form a hybrid orbital which is suitable for forming bonds between the atoms to form a compound. This mixing of hybrid orbitals is known as hybridization. The hybridization determines the geometry of the particular atom in the compound. Shortly to say
trigonal pyramidal(if one lone pair of electron is present)
bent geometry (if two lone pair of electrons are present)
To draw: To draw all the lone pair of electrons in the given compound
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Students have asked these similar questions
3. Propose a synthesis for the following transformation. Do not draw an arrow-pushing
mechanism below, but make sure to draw the product of each proposed step (3 points).
CN
+ En
CN
3) Propagation of uncertainty. Every measurement has uncertainty. In this problem, we'll
evaluate the uncertainty in every step of a titration of potassium hydrogen phthalate (a
common acid used in titrations, abbreviated KHP, formula CsH5KO4) with NaOH of an
unknown concentration.
The calculation that ultimately needs to be carried out is:
concentration NaOH
1000 x mass KHP × purity KHP
molar mass KHP x volume NaOH
Measurements:
a) You use a balance to weigh 0.3992 g of KHP. The uncertainty is ±0.15 mg (0.00015
g).
b) You use a buret to slowly add NaOH to the KHP until it reaches the endpoint. It takes
18.73 mL of NaOH. The uncertainty of the burst is 0.03 mL..
c) The manufacturer states the purity of KHP is 100%±0.05%.
d) Even though we don't think much about them, molar masses have uncertainty as well.
The uncertainty comes from the distribution of isotopes, rather than random
measurement error. The uncertainty in the elements composing KHP are:
a. Carbon:
b. Hydrogen:
±0.0008…
Don't used hand raiting and don't used Ai solution
Chapter 1 Solutions
Student Study Guide and Solutions Manual T/A Organic Chemistry
Ch. 1.2 - Prob. 1LTSCh. 1.2 - Prob. 1PTSCh. 1.2 - Prob. 2ATSCh. 1.2 - Prob. 3ATSCh. 1.2 - Prob. 4ATSCh. 1.3 - Prob. 2LTSCh. 1.3 - Prob. 5PTSCh. 1.3 - Prob. 6ATSCh. 1.3 - Prob. 7ATSCh. 1.3 - Prob. 8ATS
Ch. 1.3 - Prob. 9ATSCh. 1.3 - Prob. 3LTSCh. 1.3 - Prob. 10PTSCh. 1.3 - Prob. 11ATSCh. 1.3 - Prob. 12ATSCh. 1.4 - Prob. 4LTSCh. 1.4 - Prob. 13PTSCh. 1.4 - Prob. 14ATSCh. 1.5 - Prob. 5LTSCh. 1.5 - Prob. 15PTSCh. 1.5 - Prob. 16ATSCh. 1.6 - Prob. 6LTSCh. 1.6 - Prob. 17PTSCh. 1.6 - Prob. 18ATSCh. 1.9 - Prob. 19CCCh. 1.9 - Prob. 20CCCh. 1.9 - Prob. 21CCCh. 1.9 - Prob. 7LTSCh. 1.9 - Prob. 22PTSCh. 1.9 - Prob. 23ATSCh. 1.9 - Prob. 24CCCh. 1.10 - Prob. 8LTSCh. 1.10 - Prob. 25PTSCh. 1.10 - Prob. 26PTSCh. 1.10 - Prob. 27ATSCh. 1.10 - Prob. 28ATSCh. 1.11 - Prob. 9LTSCh. 1.11 - Prob. 29PTSCh. 1.11 - Prob. 30ATSCh. 1.11 - Prob. 31ATSCh. 1.12 - Prob. 10LTSCh. 1.12 - Prob. 32PTSCh. 1.12 - Prob. 33ATSCh. 1 - Prob. 34PPCh. 1 - Prob. 35PPCh. 1 - Prob. 36PPCh. 1 - Prob. 37PPCh. 1 - Prob. 38PPCh. 1 - Prob. 39PPCh. 1 - Prob. 40PPCh. 1 - Prob. 41PPCh. 1 - Prob. 42PPCh. 1 - Prob. 43PPCh. 1 - Prob. 44PPCh. 1 - Prob. 45PPCh. 1 - Prob. 46PPCh. 1 - Prob. 47PPCh. 1 - Prob. 48PPCh. 1 - Prob. 49PPCh. 1 - Prob. 50PPCh. 1 - Prob. 51PPCh. 1 - Prob. 52PPCh. 1 - Prob. 53PPCh. 1 - Prob. 54PPCh. 1 - Prob. 55PPCh. 1 - Prob. 56PPCh. 1 - Prob. 57PPCh. 1 - Prob. 58PPCh. 1 - Prob. 59PPCh. 1 - Prob. 60PPCh. 1 - Prob. 61PPCh. 1 - Prob. 62PPCh. 1 - Prob. 63IPCh. 1 - Prob. 67IPCh. 1 - Prob. 68IPCh. 1 - Prob. 69IPCh. 1 - Prob. 70CPCh. 1 - Prob. 71CPCh. 1 - Prob. 72CPCh. 1 - Prob. 73CPCh. 1 - Prob. 74CPCh. 1 - Prob. 75CPCh. 1 - Prob. 76CPCh. 1 - Prob. 77CP
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