(a)
Interpretation: The geometry of the central atoms has to be predicted for the given set of compounds.
Concept Introduction: According to VSEPR (Valence Shell Electron Pair Repulsion) theory, each molecule gets a unique structure. That structure is explained by considering steric number of that molecule.
The steric number is the combination of both number of σ-bonds and number of lone pairs involved in a particular molecule.
σ-bonds are formed by the mutual sharing of electrons between the two atoms. As a result, bond between two atoms is formed. This type of bond is called covalent bond. In this process, bonding electron pairs are involved.
Non-bonding electrons are not involved in the bond formation. They are called lone pairs.
The geometry of the central atom will be determined by counting the steric number followed by the hybridization state of that central atom and finally electronic arrangement of atoms in space.
If the steric number is 4, the central atom has sp3 hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be tetrahedral.
If the steric number is 3, the central atom has sp2 hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be trigonal planar.
If the steric number is 2, the central atom has sp hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be linear.
To find: The geometry for the central nitrogen atom in NH3
(b)
Interpretation: The geometry of the central atoms has to be predicted for the given set of compounds.
Concept Introduction: According to VSEPR (Valence Shell Electron Pair Repulsion) theory, each molecule gets a unique structure. That structure is explained by considering steric number of that molecule.
The steric number is the combination of both number of σ-bonds and number of lone pairs involved in a particular molecule.
σ-bonds are formed by the mutual sharing of electrons between the two atoms. As a result, bond between two atoms is formed. This type of bond is called covalent bond. In this process, bonding electron pairs are involved.
Non-bonding electrons are not involved in the bond formation. They are called lone pairs.
The geometry of the central atom will be determined by counting the steric number followed by the hybridization state of that central atom and finally electronic arrangement of atoms in space.
If the steric number is 4, the central atom has sp3 hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be tetrahedral.
If the steric number is 3, the central atom has sp2 hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be trigonal planar.
If the steric number is 2, the central atom has sp hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be linear.
To find: The geometry for the central oxygen atom in H3O+
(c)
Interpretation: The geometry of the central atoms has to be predicted for the given set of compounds.
Concept Introduction: According to VSEPR (Valence Shell Electron Pair Repulsion) theory, each molecule gets a unique structure. That structure is explained by considering steric number of that molecule.
The steric number is the combination of both number of σ-bonds and number of lone pairs involved in a particular molecule.
σ-bonds are formed by the mutual sharing of electrons between the two atoms. As a result, bond between two atoms is formed. This type of bond is called covalent bond. In this process, bonding electron pairs are involved.
Non-bonding electrons are not involved in the bond formation. They are called lone pairs.
The geometry of the central atom will be determined by counting the steric number followed by the hybridization state of that central atom and finally electronic arrangement of atoms in space.
If the steric number is 4, the central atom has sp3 hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be tetrahedral.
If the steric number is 3, the central atom has sp2 hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be trigonal planar.
If the steric number is 2, the central atom has sp hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be linear.
To find: The geometry for the central boron atom in BH4−
(d)
Interpretation: The geometry of the central atoms has to be predicted for the given set of compounds.
Concept Introduction: According to VSEPR (Valence Shell Electron Pair Repulsion) theory, each molecule gets a unique structure. That structure is explained by considering steric number of that molecule.
The steric number is the combination of both number of σ-bonds and number of lone pairs involved in a particular molecule.
σ-bonds are formed by the mutual sharing of electrons between the two atoms. As a result, bond between two atoms is formed. This type of bond is called covalent bond. In this process, bonding electron pairs are involved.
Non-bonding electrons are not involved in the bond formation. They are called lone pairs.
The geometry of the central atom will be determined by counting the steric number followed by the hybridization state of that central atom and finally electronic arrangement of atoms in space.
If the steric number is 4, the central atom has sp3 hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be tetrahedral.
If the steric number is 3, the central atom has sp2 hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be trigonal planar.
If the steric number is 2, the central atom has sp hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be linear.
To find: The geometry for the central boron atom in BCl3
(e)
Interpretation: The geometry of the central atoms has to be predicted for the given set of compounds.
Concept Introduction: According to VSEPR (Valence Shell Electron Pair Repulsion) theory, each molecule gets a unique structure. That structure is explained by considering steric number of that molecule.
The steric number is the combination of both number of σ-bonds and number of lone pairs involved in a particular molecule.
σ-bonds are formed by the mutual sharing of electrons between the two atoms. As a result, bond between two atoms is formed. This type of bond is called covalent bond. In this process, bonding electron pairs are involved.
Non-bonding electrons are not involved in the bond formation. They are called lone pairs.
The geometry of the central atom will be determined by counting the steric number followed by the hybridization state of that central atom and finally electronic arrangement of atoms in space.
If the steric number is 4, the central atom has sp3 hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be tetrahedral.
If the steric number is 3, the central atom has sp2 hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be trigonal planar.
If the steric number is 2, the central atom has sp hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be linear.
To find: The geometry for the central boron atom in BCl4−
(f)
Interpretation: The geometry of the central atoms has to be predicted for the given set of compounds.
Concept Introduction: According to VSEPR (Valence Shell Electron Pair Repulsion) theory, each molecule gets a unique structure. That structure is explained by considering steric number of that molecule.
The steric number is the combination of both number of σ-bonds and number of lone pairs involved in a particular molecule.
σ-bonds are formed by the mutual sharing of electrons between the two atoms. As a result, bond between two atoms is formed. This type of bond is called covalent bond. In this process, bonding electron pairs are involved.
Non-bonding electrons are not involved in the bond formation. They are called lone pairs.
The geometry of the central atom will be determined by counting the steric number followed by the hybridization state of that central atom and finally electronic arrangement of atoms in space.
If the steric number is 4, the central atom has sp3 hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be tetrahedral.
If the steric number is 3, the central atom has sp2 hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be trigonal planar.
If the steric number is 2, the central atom has sp hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be linear.
To find: The geometry for the central carbon atom in CCl4
(g)
Interpretation: The geometry of the central atoms has to be predicted for the given set of compounds.
Concept Introduction: According to VSEPR (Valence Shell Electron Pair Repulsion) theory, each molecule gets a unique structure. That structure is explained by considering steric number of that molecule.
The steric number is the combination of both number of σ-bonds and number of lone pairs involved in a particular molecule.
σ-bonds are formed by the mutual sharing of electrons between the two atoms. As a result, bond between two atoms is formed. This type of bond is called covalent bond. In this process, bonding electron pairs are involved.
Non-bonding electrons are not involved in the bond formation. They are called lone pairs.
The geometry of the central atom will be determined by counting the steric number followed by the hybridization state of that central atom and finally electronic arrangement of atoms in space.
If the steric number is 4, the central atom has sp3 hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be tetrahedral.
If the steric number is 3, the central atom has sp2 hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be trigonal planar.
If the steric number is 2, the central atom has sp hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be linear.
To find: The geometry for the central carbon atom in CHCl3
(h)
Interpretation: The geometry of the central atoms has to be predicted for the given set of compounds.
Concept Introduction: According to VSEPR (Valence Shell Electron Pair Repulsion) theory, each molecule gets a unique structure. That structure is explained by considering steric number of that molecule.
The steric number is the combination of both number of σ-bonds and number of lone pairs involved in a particular molecule.
σ-bonds are formed by the mutual sharing of electrons between the two atoms. As a result, bond between two atoms is formed. This type of bond is called covalent bond. In this process, bonding electron pairs are involved.
Non-bonding electrons are not involved in the bond formation. They are called lone pairs.
The geometry of the central atom will be determined by counting the steric number followed by the hybridization state of that central atom and finally electronic arrangement of atoms in space.
If the steric number is 4, the central atom has sp3 hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be tetrahedral.
If the steric number is 3, the central atom has sp2 hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be trigonal planar.
If the steric number is 2, the central atom has sp hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be linear.
To find: The geometry for the central carbon atom in CH2Cl2
Want to see the full answer?
Check out a sample textbook solution
Chapter 1 Solutions
Student Study Guide and Solutions Manual T/A Organic Chemistry
- Part 9 of 9 Consider the products for the reaction. Identify the major and minor products. HO Cl The E stereoisomer is the major product and the Z stereoisomer is the minor product ▼ S major product minor productarrow_forwardConsider the reactants below. Answer the following questions about the reaction mechanism and products. HO Clarrow_forwardjulietteyep@gmail.com X YSCU Grades for Juliette L Turner: Orc X 199 A ALEKS - Juliette Turner - Modul X A ALEKS - Juliette Turner - Modul x G butane newman projection - Gox + www-awa.aleks.com/alekscgi/x/Isl.exe/10_u-IgNslkr7j8P3jH-IBxzaplnN4HsoQggFsejpgqKoyrQrB2dKVAN-BcZvcye0LYa6eXZ8d4vVr8Nc1GZqko5mtw-d1MkNcNzzwZsLf2Tu9_V817y?10Bw7QYjlb il Scribbr citation APA SCU email Student Portal | Main Ryker-Learning WCU-PHARM D MySCU YSCU Canvas- SCU Module 4: Homework (Ch 9-10) Question 28 of 30 (1 point) | Question Attempt: 1 of Unlimited H₂SO heat OH The mechanism of this reaction involves two carbocation intermediates, A and B. Part 1 of 2 KHSO 4 rearrangement A heat B H₂O 2 OH Draw the structure of A. Check Search #t m Save For Later Juliet Submit Assignm 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessarrow_forward
- The electrons flow from the electron-rich atoms of the nucleophile to the electrons poor atoms of the alkyl halide. Identify the electron rich in the nucleophile. Enter the element symbol only, do not include any changes.arrow_forwardHello, I am doing a court case analysis in my Analytical Chemistry course. The case is about a dog napping and my role is prosecution of the defendant. I am tasked in the Area of Expertise in Neutron Activation and Isotopic Analysis. Attached is the following case study reading of my area of expertise! The landscaping stone was not particularly distinctive in its decoration but matched both the color and pattern of the Fluential’s landscaping stone as well as the stone in the back of the recovered vehicle. Further analysis of the stone was done using a technique called instrumental neutron activation analysis. (Proceed to Neutron Activation data) Photo Notes: Landscaping stone recovered in vehicle. Stone at Fluential’s home is similar inappearance. Finally, the white paint on the brick was analyzed using stable isotope analysis. The brick recovered at the scene had smeared white paint on it. A couple of pieces of brick in the back of the car had white paint on them. They…arrow_forwardCite the stability criteria of an enamine..arrow_forward
- What would you expect to be the major product obtained from the following reaction? Please explain what is happening here. Provide a detailed explanation and a drawing showing how the reaction occurs. The correct answer to this question is V.arrow_forwardPlease answer the question for the reactions, thank youarrow_forwardWhat is the product of the following reaction? Please include a detailed explanation of what is happening in this question. Include a drawing showing how the reagent is reacting with the catalyst to produce the correct product. The correct answer is IV.arrow_forward
ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage Learning
ChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill Education
Principles of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill Education
Chemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage Learning
Elementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY