Physics: Principles with Applications
6th Edition
ISBN: 9780130606204
Author: Douglas C. Giancoli
Publisher: Prentice Hall
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Chapter 1, Problem 22P
Solution
a.
Total meters in 1 light year.
9.45×1015 m
Given:
A light year is the distance light travels in one year at speed 2.998×108m/sec
Formula used:
d=v×t here d is distance, v is velocity and t is time
Calculation:
One year =365 days = 365×24×60×60 Second
So one light year = v×t meters
One light year = 2.998×108×365×24×60×60 meter
One light year = 9.45×1015 m
Conclusion:
Therefore, in 1 light year there are 9.45×1015 m
b.
Total AU in 1 light year.
One light year =6.3×104 AU.
Given information:
A light year is the distance light travels in one year at speed 2.998×108m/sec. An astronomical unit (AU) is the average distance from sun to earth , 1.5×108km.
Formula used:
1AU= 1.5×108km1AU= 1.5×1011m
Calculation:
One light year is equal to 9.45×1015
So, number of AU in 1.00 light year=
9.45×10151.5×1011=6.3×104
Conclusion:
Therefore, number of AU in 1 light year is 6.3×104
c.
The speed of light in AU/h.
7.20AU/hour
Given:
A light year is the distance light travels in one year at speed 2.998×108m/sec
Formula used:
1km=1000 m
1 hour=3600sec
Calculation:
The speed of light in meter/sec is 2.998×108
In km/sec the speed of light =2.998×1081000=2.998×105 km/sec
In km/hour Speed of light
=2.998×105×3600 km/hour
One AU is equal to 1.5×108km
So the speed of light in AU/h
=2.998×105×36001.5×108=1.07928×1091.5×108=7.20 AU/hour
Conclusion:
Therefore, speed of light is 7.2 AU/hour.
Chapter 1 Solutions
Physics: Principles with Applications
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