Physics: Principles with Applications
Physics: Principles with Applications
6th Edition
ISBN: 9780130606204
Author: Douglas C. Giancoli
Publisher: Prentice Hall
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Chapter 1, Problem 8P
To determine

Add (9.2×103s)+(8.3×104s)+(0.008×106s).

Expert Solution & Answer
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Answer to Problem 8P

1.002×105s

Explanation of Solution

Given:

(9.2×103s)+(8.3×104s)+(0.008×106s)

Calculation:

Let us first simplify the numbers separately and then add them.

9.2×103=9.2×1000 s=9200s

Now, simplify 8.3×104s.

8.3×104s = 8.3×10000 s=83000 s

Finally, simplify 0.008 × 106s.

0.008 × 106s=0.008×1000000s=8000 s

Now, add the simplified values to get the value of the given expression.

9200 s+83000 s+8000 s=100,200 s

The value of 100,200 s in scientific notation becomes 1.002×105s.

Conclusion:

The value of the addition 9.2 × 103s + 8.3 × 104s + 0.008 × 106s is 1.002 × 105.

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Physics: Principles with Applications

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