Physics: Principles with Applications
Physics: Principles with Applications
6th Edition
ISBN: 9780130606204
Author: Douglas C. Giancoli
Publisher: Prentice Hall
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Chapter 1, Problem 16P

(a)

To determine

The conversion factor between ft2and yard2 .

(a)

Expert Solution
Check Mark

Answer to Problem 16P

The conversion factor is 1ft2=0.111yard2

Explanation of Solution

Given:

The units are ft2and yard2

Formula used:

1 feet = 0.3333 yards

Calculation:

Since 1 feet = 0.3333 yards

So,

  1ft=0.333yard1ft2=0.3332yard21ft2=0.111yard2

Conclusion:

Thus, the conversion factor is 1ft2=0.111yard2

(b)

To determine

The conversion factor between m2and ft2 .

(b)

Expert Solution
Check Mark

Answer to Problem 16P

The conversion factor is

  1m2=10.76ft2

Explanation of Solution

Given:

The units are ft2and m2

Formula used:

1 m = 3.28 ft

Calculation:

Since 1 m = 3.28 ft

So,

  1m=3.28ft1m2=3.282ft21m2=10.76ft2

Conclusion:

Thus, the conversion factor is

  1m2=10.76ft2

Chapter 1 Solutions

Physics: Principles with Applications

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