Chapter 1, Problem 12P

Write the following as full (decimal) numbers without prefixes on the units: (a) 286.6mm, (b) 85µV, (c) 760 mg. (d) 62.1 ps, (e) 22.5nm, (f)2.50 gigavolts.

To determine

The following as full (decimal) numbers without prefixes on the units:

286.6 mm

Answer to Problem 12P

Solution:

  $0.2866=2.866\times {10}^{(-1)}\text{m}$

Explanation of Solution

Given:

The value 0f 286.6 mm is converted to meter.

Calculation:

The value is divided by ${10}^3$ because $1\text{m}\text{=}\text{1000}\text{mm}$ . Here the decimal is moved one place to the right such that it is right to the leftmost non-zero number.

Conclusion:

  $286.6\text{ mm }=0.2866\text{ m}$

To determine

The following as full (decimal) numbers without prefixes on the units:

85 µV

Answer to Problem 12P

Solution:

  $85\times {10}^{(-6)}\text{Volts}=8.5\times {10}^{(-5)}\text{Volts}$

Explanation of Solution

Given:

The value of $85\text{ µV}$ is in µV, it is converted to Volts.

To determine

The following as full (decimal) numbers without prefixes on the units:

760 mg

Answer to Problem 12P

Solution:

  $\text{0}\text{.76}\text{g}\text{=}\text{7}{\text{.6×10}}^{\text{(-1)}}\text{g}$

Explanation of Solution

Given:

The value of760 mgis in mg, it is converted to the gram.

Solution:

To do so the value is divided by ${10}^3$ because $1\text{g}=1\times {10}^{(-3)}\text{mg}$

Here the decimal is moved one place to the right such that it is right to the leftmost non-zero number.

Conclusion:

  $0.76\text{mg}=7.6\times {10}^{(-1)}\text{g}$

To determine

The following as full (decimal) numbers without prefixes on the units:

  $6.21\text{ps}$

Answer to Problem 12P

Solution:

  $62.1\times {10}^{(-12)}\text{s}=6.21\times {10}^{(-13)}\text{s}$

Explanation of Solution

Given:

The value of $6.21\text{ps}$ is in picoseconds, it is converted to second.

To determine

The following as full (decimal) numbers without prefixes on the units:

22.5 nm

Answer to Problem 12P

Solution: $22.5\times {10}^{(-9)}\text{m}=2.25\times {10}^{(-10)}\text{m}$

Explanation of Solution

Since the value is in nm (nanometre), it is converted to meter. To do so the value is divided by 10-9 because $\text{1m}{\text{= 1×10}}^{\text{(-9)}}\text{nm}\text{.}$

Here, the decimal is moved one place to the left such that it is right to the leftmost non-zero number.

To determine

The following as full (decimal) numbers without prefixes on the units:

2.50 gigavolts

Answer to Problem 12P

Solution: $\text{2}{\text{.50×10}}^{\text{9}}\text{Volts}$

Explanation of Solution

Since the value is in gigavolts, it is converted to Volts. To do so the value is multiplied by ${10}^9$ because $\text{1gigavolts}{\text{= 1×10}}^{\text{9}}\text{ Volts}\text{.}$

Conclusion:

  $\text{2}\text{.50}\text{gigavolts = 2}{\text{.50 ×10}}^{\text{9}}\text{ Volts}$