Physics: Principles with Applications
Physics: Principles with Applications
6th Edition
ISBN: 9780130606204
Author: Douglas C. Giancoli
Publisher: Prentice Hall
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Chapter 1, Problem 53GP

(a)

To determine

The percent uncertainty in θ and sinθ .

(a)

Expert Solution
Check Mark

Answer to Problem 53GP

The percent uncertainty in θ is 3.33%.

The percent uncertainty in sinθ is 3.25%.

Explanation of Solution

Given:

The angle θ=15°±0.5°

Formula used:

The expression for percent uncertainty in θ is,

  %uncertainty in θ=Δθθ×100%

Here, Δθ is the uncertainty and θ is the measured value.

The expression for percent uncertainty in sinθ is,

  %uncertainty in sinθ=Δsinθsinθ×100%

Here, Δsinθ is the uncertainty and sinθ is the measured value.

Calculation:

The percent uncertainty in θ is,

  %uncertainty in θ=Δθθ×100%=15.5°15°15°×100=3.33%

The percent uncertainty in sinθ is,

  %uncertainty in sinθ=Δsinθsinθ×100%=sin15.5°sin15°sin15°×100=3.25%

Conclusion:

Thus, the percent uncertainty in θ is 3.33% and the percent uncertainty in sinθ is 3.25%.

(b)

To determine

The percent uncertainty in θ and sinθ .

(b)

Expert Solution
Check Mark

Answer to Problem 53GP

The percent uncertainty in θ is 0.67%.

The percent uncertainty in sinθ is 0.23%.

Explanation of Solution

Given:

The angle θ=75°±0.5°

Formula used:

The expression for percent uncertainty in θ is,

  %uncertainty in θ=Δθθ×100%

Here, Δθ is the uncertainty and θ is the measured value.

The expression for percent uncertainty in sinθ is,

  %uncertainty in sinθ=Δsinθsinθ×100%

Here, Δsinθ is the uncertainty and sinθ is the measured value.

Calculation:

The percent uncertainty in θ is,

  %uncertainty in θ=Δθθ×100%=75.5°75°75°×100=0.67%

The percent uncertainty in sinθ is,

  %uncertainty in sinθ=Δsinθsinθ×100%=sin75.5°sin75°sin75°×100=0.23%

Conclusion:

Thus, the percent uncertainty in θ is 0.67% and the percent uncertainty in sinθ is 0.23%.

Chapter 1 Solutions

Physics: Principles with Applications

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