
Concept explainers
To find: Data is sample or population and then find range, variance and standard deviation.

Answer to Problem 4E
Range=49, 19, Variance=210.446, 42.265, Standard deviation=14.5, 6.5
Explanation of Solution
Given information:
Calculation:
It is a sample data because we know exactly it is about two different rides and not all of them.
To find mean, add all observations and divide it by total number of observations.
The mean of ride A is 38.4 and mean of ride B is 40.6
The range is the difference between the highest and lowest value.
Ride A, 60−11=49Ride B, 50−31=19
The variance is the average square deviation from the mean.
First add all numbers from each set and calculate the square then divide it with the number of integers in set.
A=4612=212521, 212521/12=17710.08B=4872=237169, 237169/12=19764.08
Second we take every integer from each set and calculate square of them and add all together.
A=112+222+⋯=20025B=312+322+⋯=20299
Third, we subtract integers from second step with ones from first step.
20025−17710.08=2314.91620229−1976.08=464.916
Fourth, take integers from third step and divide them with total number of integers in set of minus one. Which means 12 − 1 = 11.
2314.91611=210.446464.91611=42.265
The standard deviation is the average deviation from the mean. It is found by taking the square root of the variance.
√210.446=14.5√42.265=6.5
Thus, Range=49, 19, Variance=210.446, 42.265, Standard deviation=14.5, 6.5
Chapter 0 Solutions
Glencoe Algebra 2 Student Edition C2014
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