Chapter 0.2, Problem 5E

To determine

the product.

Answer to Problem 5E

  $\left(b+4\right)\left(b-3\right)=b^2+b-12$

Explanation of Solution

Given information :

  $\left(b+4\right)\left(b-3\right)$

It is given that $\left(b+4\right)\left(b-3\right)$

So,

  $\begin{array}{c}\left(b+4\right)\left(b-3\right)=b\left(b-3\right)+4\left(b-3\right)\\ b\left(b-3\right)+4\left(b-3\right)=b^2-3b+4b-12\\ b^2-3b+4b-12=b^2+b-12\end{array}$

So,

  $\left(b+4\right)\left(b-3\right)=b^2+b-12$