Chapter 0.2, Problem 3E

To determine

the product.

Answer to Problem 3E

  $\left(h+4\right)\left(h-4\right)=h^2-16$

Explanation of Solution

Given information :

  $\left(h+4\right)\left(h-4\right)$

It is given that $\left(h+4\right)\left(h-4\right)$

So,

  $\begin{array}{c}\left(h+4\right)\left(h-4\right)=h\left(h-4\right)+4\left(h-4\right)\\ h\left(h-4\right)+4\left(h-4\right)=h^2-4h+4h-16\\ h^2-4h+4h-16=h^2-16\end{array}$

So,

  $\left(h+4\right)\left(h-4\right)=h^2-16$