Chapter 0, Problem 10PO

To determine

The expressions for height, width and area of the rectangle

Answer to Problem 10PO

The width = x, height = $(2x-3)$ , area = $(2x^2-3x)$ .

Explanation of Solution

Given information:

The height of the rectangle is 3 mm less than twice the width.

Calculation:

Let, the width of the rectangle be x mm.

Twice of x = $2\times x=2x$ .

Height of the rectangle is 3 mm less than $2x$ .

  $\therefore$ Height = $(2x-3)$ mm.

Area of rectangle is

  $\begin{array}{l}height\times width\\ =(2x-3)\times (x)\\ =(2x)(x)-3(x)\\ =2x^2-3x\end{array}$

  $\therefore$ Are of rectangle = $(2x^2-3x)m{m}^2$ .