Using the block diagram or solution, show that the expected gain in the transfer function CA' (s)/Q'(s) is negative. Please explain how to approach this. No typed answers where the equation is in one line and it's hard to understand, please дома dela 1 C_AO G2(s) G3(5) dCA(t) dt dT' (t) dt = 2 Q beta 3-a G1(s) G4(s) (-AHko E koe RT + EKOČA RT2 E e E F T' (t) + Co (t) E 1 (All) (- -)+(y) = pcp eRT CA(t) + Е КОСАДНЕ PCPRT2 eRT T'(t) + Q'(t) 2 T
Using the block diagram or solution, show that the expected gain in the transfer function CA' (s)/Q'(s) is negative. Please explain how to approach this. No typed answers where the equation is in one line and it's hard to understand, please дома dela 1 C_AO G2(s) G3(5) dCA(t) dt dT' (t) dt = 2 Q beta 3-a G1(s) G4(s) (-AHko E koe RT + EKOČA RT2 E e E F T' (t) + Co (t) E 1 (All) (- -)+(y) = pcp eRT CA(t) + Е КОСАДНЕ PCPRT2 eRT T'(t) + Q'(t) 2 T
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Transcribed Image Text:Using the block diagram or solution, show that the expected gain in the transfer
function CA' (s)/Q'(s) is negative. Please explain how to approach this. No typed
answers where the equation is in one line and it's hard to understand, please
дома
dela
1
C_AO
G2(s)
G3(5)
dCA(t)
dt
dT' (t)
dt
=
2
Q
beta
3-a
G1(s)
G4(s)
(-AHko
E
koe RT
+
EKOČA
RT2
E
e
E
F
T' (t) + Co (t)
E
1
(All) (- -)+(y)
=
pcp
eRT CA(t) +
Е КОСАДНЕ
PCPRT2
eRT T'(t) +
Q'(t)
2
T
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