The enzyme lysozyme kills certain bacteria by attacking asugar called N-acetylglucosamine (NAG) in their cell walls.At an enzyme concentration of 2 × 10-6 M, the maximumrate for substrate (NAG) reaction, found at high substrateconcentration, is 1 × 10-6 mol L¯'s1. The rate is reducedby a factor of 2 when the substrate concentration isreduced to 6 x 10-6 M. Determine the Michaelis-Mentenconstants Km and k, for lysozyme.

Enzymes are proteinaceous substances which are capable of catalyzing chemical reactions of…

Answered: The enzyme lysozyme kills certain…

Biochemistry

9th Edition

ISBN:9781319114671

Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Chapter1: Biochemistry: An Evolving Science

Section: Chapter Questions

Problem 1P

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An enzyme-catalyzed reaction has a KM of 20.0 mmol L-1 and Vmax of 17.0 pmol s-1. When a mixed inhibitor is added, the apparent KM is 50.0 mmol L-1 and the apparent Vmax is 5.20 pmol s-1. Calculate α.
you are trying to come up with a drug to inhibit the activity of an enzyme thuogth to have a role in a liver disease. in the lab the enzyme was shown to have a Km of 1x10-6 M and Vmax of 0.1 micromoles/min.mg measruing at room temperature. you developed a mixed non-competitve inhibitor with a ki=0.4x10-6M and a Ki` pf 0/2 x 10-5 What will be the apparent Km in the presence of 1.0x10-6 M?
How can you find Kcat if you are only given Vmax, Km and [E] ? I tried using Kcat=Vmax/[E] but that didn't work. How do you know if [E] is the same as [E]total, and if it isn't how do you find it from this information: The Vmax for a particular enzyme is 10 nmols/L/s. The Km for its substrate is 5 microM. If the enzyme concentration is 10 nM, what is the kcat? a.80 nmoles/L/s b.8000 nmoles/L/s c.2 nmoles/L/s d.50 nmoles/L/s
The table contains data about how different ASFV mutants affect enzyme activity-- for example the D29A mutant, where the D at position 29 was mutated to an A. Select three mutants at random, and for each mutant explain how that mutation could affect intermolecular force interactions (an example: hydrogen bonding could be disrupted by this mutation because…
82.16
a particular enzyme catalyzes a single reactant S to a single product P, following michaelis-menten kinetics rp=(VmaxCs) / (Km + Cs) 1. A reaction with this enzyme is carried out at very low substrate concentrations. Draw and label a curve on the plot that describes the reaction kinetics under those conditions.
Phosphoglycerate-mutase catalyses the isomerization of 3-phospho-glycerate to 2-phospho-glycerate. The enzyme has a molecular weight of 28,556 g/mol. In assays using 1 milligram of enzyme per assay the Km for 3-phosphoglycerate was 1.2 x 10^-3M and the Vmax was 840 μmole min^-1. What would be the Vmax in units of mole s^-1?
In a alkaline phosphatase kinetics experiments a studnet first made a standard curve with different amounts of PNP. In a reaction carried out with 10nM alkaline phosphatase and 100 uM PNPP substrate the student measured an absorbance value of 0.76 at 410nm after 30 seconds of reaction. Assuming the 30 second time point is in the lienar range of the reaction and the substrate has not been depleted at this time point, calculate the Vo at 100uM PNPP (in units of concentration per time).Beer's law formula given is y=0.0323x (y axis is Absorbance) (x Axis is PNP uM)
From a kinetics experiment, kcat was determined to be 295sec-1. For the kinetic assay, 0.3mL of a 0.25mg/mL solution of enzyme was used, and the enzyme has a molecular weight of 125,000 g/mole. Assume a reaction volume of 3mL. Calculate Vmax (µM∙min-1) for the enzyme and catalytic efficiency ( in M-1sec-1) for the enzyme. The Km for the enzyme was determined to be 2.55 x 10-2M.
In a pUC19 digest for 1 ug of pUC19 (DNA conc. 282ng/ul) using 10X Cutsmart buffer, pure water and BamHI enzyme in a total volume of 40 ul, how much of each solution is added to the total volume?
If the enzyme lactase has a Vo of 0.111111111111 mM per minute when [S] = 1.0 mM, and a Vo of 0.20 mM per minute when [S] = 5.0 mM, what is its Km? 0.125 mM 0.25 mM 0.50 mM 1.25 mM 5.0 mM
You are working on an enzyme that obeys standard Michaelis-Menten kinetics. Based on the following reaction expression, what is the Km value for this enzyme? E+SESE + P . . . k₁ = 880.8 M-¹5-1 k.₁ = 42.18 S-1 k₂ = 56.29 S-1

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