Below is a diagram in which product formation over time is shown for several substrate concentrations[S], as a result of enzyme action. Indicate whether the statements below are true or false:Product concentration, [P]The diagram shows that:Time1I[S] = 1.0 μM[S] = Km = 0.5 μM[S] = 0.2 μMthe amount of product formed depends upon the Km of the enzymeSChoose...IM200 00ORDIKEROC13:42 ( Product coThe diagram shows that:TimeOI11[S] = 0.2 μmthe amount of product formed depends upon the Km of the enzymeafter enough time, each of these three curves would be expected to reach amaximum product concentrationproduct formation increases at the same rate for the duration of eachexperimentas substrate concentration [S] decreases, the initial velocity of the reactionalso decreases.μMChoose...Choose...Choose...Choose...Report qu

Before going into the question, we need to be clear about what 'km' is. 'Km' is the Michaelis-Menten…

Answered: The diagram shows that: the amount of…

Basic Clinical Laboratory Techniques 6E

6th Edition

ISBN:9781133893943

Author:ESTRIDGE

Publisher:ESTRIDGE

Chapter6: Basic Clinical Chemistry

Section6.5: Blood Glucose And Hemoglobin A1c

Problem 8RQ

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Energetic of Fructose-1 ,6-bis P Hydrolysis (Integrates with Chapter 3.) The standard free energy change (G) for hydrolysis of fructose-1. 6-bisphosphate (FBP) to fructose-S-phosphate (F-6-P) and P: is -16.7 KJ/mol: FBP + H2O fructose-6-P + Pi The standard free energy change (G) for ATP hydrolysis is -30.5 KJ/mol: ATP + H2O ADP + Pj What is the standard free energy change for the phosphofructokinase reaction: ATP + fructose-6-P ADP + FBP b. What is the equilibrium constant for this reaction? c. Assuming the intracellular concentrations of [ATP] and (ADP] are maintained constant at 4 mM and 1.6 mM, respectively, in a rat liver cell, what will be the ratio of [FBP]/[fructose-6-P] when the phosphofructokinase reaction reaches equilibrium?

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