The arm angle, e (t), is controlled by a closed-loop system. The input (reference) to the system is the desired angle, and the output is the actual angle. A controller uses the difference between the desired angle and the actual angle to drive the motor, resulting in a motor torque applied to the system. motor torque(t) houlder joint damping(B) The customer wants to make a system to have 1) O steady-state error 2) Less than 10% overshoot 3) Less than 1- For a step inp **ling time Arm length (/) Mass(m) g design a controller to meet the design spec above. 1) Design a controller to meet the design spec. 2) Evaluate your controller using step response (time response) 3) Evaluate your closed-loop system using frequency response (e.g., Bandwidth, Gain margin. Phase margin). b) I(s) Control Error (E) Reference (R) Controller (C) Signal (V.) !Output (8) Plant Dynamics (P) Ө a) P(s) please clearly specify your assumptions and approaches. The arm is actuated by a motor (Fig. 1(a)), with a schematic shown below. R mutur Vs Vm tonque(t=) shoulder join damping B Arm length (1) g (a) Masy(m) (b) Fig 1. Inverted pendulum system schematics (mass = 10kg, g = 10 m/s², arm length = 1 m, damping ratio = (5/Team_number) +0.5 Nms/rad). • Gear ratio, etc. not given in the documents can be defined with your assumption.

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Chapter22: Basics Of Electronics And Computer Systems
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The arm angle, e (t), is controlled by a closed-loop system. The input (reference) to the system
is the desired angle, and the output is the actual angle. A controller uses the difference
between the desired angle and the actual angle to drive the motor, resulting in a motor torque
applied to the system.
motor
torque(t)
houlder joint
damping(B)
The customer wants to make a system to have
1) O steady-state error
2) Less than 10% overshoot
3) Less than 1-
For a step inp
**ling time
Arm length (/)
Mass(m)
g
design a controller to meet the design spec above.
1) Design a controller to meet the design spec.
2) Evaluate your controller using step response (time response)
3) Evaluate your closed-loop system using frequency response (e.g., Bandwidth,
Gain margin. Phase margin).
Transcribed Image Text:The arm angle, e (t), is controlled by a closed-loop system. The input (reference) to the system is the desired angle, and the output is the actual angle. A controller uses the difference between the desired angle and the actual angle to drive the motor, resulting in a motor torque applied to the system. motor torque(t) houlder joint damping(B) The customer wants to make a system to have 1) O steady-state error 2) Less than 10% overshoot 3) Less than 1- For a step inp **ling time Arm length (/) Mass(m) g design a controller to meet the design spec above. 1) Design a controller to meet the design spec. 2) Evaluate your controller using step response (time response) 3) Evaluate your closed-loop system using frequency response (e.g., Bandwidth, Gain margin. Phase margin).
b) I(s)
Control
Error (E)
Reference (R)
Controller
(C)
Signal (V.)
!Output (8)
Plant
Dynamics (P)
Ө
a) P(s)
please clearly specify your assumptions and approaches.
The arm is actuated by a motor (Fig. 1(a)), with a schematic shown below.
R
mutur
Vs
Vm
tonque(t=)
shoulder join
damping B
Arm length (1)
g
(a)
Masy(m)
(b)
Fig 1. Inverted pendulum system schematics (mass = 10kg, g = 10 m/s², arm length = 1 m,
damping ratio = (5/Team_number) +0.5 Nms/rad).
•
Gear ratio, etc. not given in the documents can be defined with your assumption.
Transcribed Image Text:b) I(s) Control Error (E) Reference (R) Controller (C) Signal (V.) !Output (8) Plant Dynamics (P) Ө a) P(s) please clearly specify your assumptions and approaches. The arm is actuated by a motor (Fig. 1(a)), with a schematic shown below. R mutur Vs Vm tonque(t=) shoulder join damping B Arm length (1) g (a) Masy(m) (b) Fig 1. Inverted pendulum system schematics (mass = 10kg, g = 10 m/s², arm length = 1 m, damping ratio = (5/Team_number) +0.5 Nms/rad). • Gear ratio, etc. not given in the documents can be defined with your assumption.
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