The force of gravity acting on the smooth uniform bar is 15 N. Find the reactions at the supports7: What are the reaction forces at point A? Indicate the magnitude (in Newtons) and direction withan arrow.8: What is the reaction force at point B? Indicate the magnitude (in Newtons).7 m50°A30°BGiven Answers7. Ax=5.75N, Ay=10.18N ↑8. BN=7.5N

Answered: Image /qna-images/answer/2882bd36-8edd-4d9d-9b75-3f3ee84c39de.jpg

Answered: The force of gravity acting on the…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Three forces are applied to the beam. F2 = (-200 + 600 ĵ -250 K) N. Z F2 d3. d2 HD d1 F1 F3 + Values for the figure are given in the following table. Note the figure may not be to scale. Variable Value F₁ 250 N F3 400 N d₁ 1 m d2 4 m d3 0.5 m a. Replace the force system with an equivalent force, FR , express as a cartesian vector. b. Replace the force system with an equivalent couple moment acting at point O, (MR)o, express as a cartesian vector. Round your final answers to 3 significant digits/figures. F = R (MR)O = m + 2 + 2 + k) N ) N-
What are the tensions in each of the 4 cables supporting the lamp, if the lamp weighs 40 Ibs and the coordinate direction angles for Cable B are a = 95°, ß = 140° and y = 50.44°? Cable B Cable A 30° 50 Cable C 1 ft 3 ft Cable D 4 Using the figure from Question 3, determine the maximum weight of the lamp if no cable can support more than 75 Ibs of tension? You can reuse the Cartesian force vector expressions for TA, TB and Tc from Question 3 i.e. you do not need to derive them again for this question.
Replace the loading (F1 and F2) by an equivalent resultant force and couple moment at point A. Enter your responses in the blanks provided. Upload your workings. What is the magnitude of the resultant force? Enter your response in Newtons to three significant figures.
4
only HANDWRITTEN answer needed ( NOT TYPED)
Use the method of SECTIONS to find the true magnitude and direction in bar HG of the truss shown below in Fig 3.5 -500lb -100lb A 45° -200lb H -100lb 2 B -200lb -200lb MAGNITUDE AND DIRECTION OF SUPPORTS -500lb H -100lb 45° 2¹ C2D 2¹ Fig 3.5. -200lb -100lb LI 2 B 2₁ 2₁ D 2₁ E
6
A transmission tower (a truss) for supporting electric wires is shown. The load of wire at D is shown as force F1 at an angle of a and the load of wire at A is shown as force F2 at an angle of B. Using the values given in the table below: F1 (N) F: (N) a (deg) B (deg) w (m) h (m) Value 150 70 30 60 2 a) Find the reaction forces at supports Y and Z. b) Determine the forces supported by members DO, DM, SV, and UX and specify whether the member is in Tension or Compression. M Q B F1 F2 T W X h
= Q3. As shown on the right in image below, the force Facting on the box varies with displacement s, and the coefficient in the image, C = 18. Determine the work done by force F to the box when the box has displaced s 1.8 m. Please pay attention: the numbers may change since they are randomized. Negative sign must be included if the work done is negative. Your answer must include 2 places after the decimal point, and proper Sl unit. F Your Answer: Answer - S units F (N) C 1 2 s (m)
3m Find the rectangular representation of the force F, given that its magnitude 240 N. * F = -135.76 i+ 169.71 j– 101.82 k F = 135.76 i + 169.71 j+ 101.82 k F = 135.76 i - 169.71 j+ 101.82 k F = -135.76i+ 169.71 j+ 101.82 k
Question 2 Find the value of a (in mm) for which the magnitude of the reaction at B is equal to 800 N. (X,XX,XXX represents the last digits number of your IC) 3 A 357 N 240 mm- B 4 87mm T
Q13. As shown in the image below, the member is subjected to the applied loads: a free couple moment M=320lb*ft, concentrated force F1=380lb, and concentrated force F2=220lb. The dimension a=5.5ft. Determine the magnitude of the resulatant moment (in lb*ft) caused by these applied loads about point A. Answer must inculde 1 place after the decimal point.

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