Three forces are applied to the beam. F2 = (-200 + 600 ĵ-250 K) N.ZF2d3.d2HDd1F1F3+Values for the figure are given in the following table. Notethe figure may not be to scale.VariableValueF₁250 NF3400 Nd₁1 md24 md30.5 ma. Replace the force system with an equivalent force, FR, express as a cartesian vector.b. Replace the force system with an equivalent couplemoment acting at point O, (MR)o, express as acartesian vector.Round your final answers to 3 significant digits/figures.F=R(MR)O =m+2 +2 +k) N) N-

a) F1= 250 (-k) ; F2 = -200 i + 600 j -250 k & F3 = 400 jFR = F1 + F2 + F3 = -250 k -200 i +600…

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International Edition---engineering Mechanics: Statics, 4th Edition

4th Edition

ISBN:9781305501607

Author:Andrew Pytel And Jaan Kiusalaas

Publisher:Andrew Pytel And Jaan Kiusalaas

Chapter1: Introduction To Statics

Section: Chapter Questions

Problem 1.12P: A differential equation encountered in the vibration of beams is d4ydx4=2D where x = distance...

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