NPTWaterна√5-77P₁ = 300 kPaT₁ = 20°Cd=50mmFind: M- total head; p- total pressure.Q- Volumetric flow vatem-mass flow rateN - paverRe-Reynold's number

Answered: NPT Water на √5-77 P₁ = 300 kPa T₁ =…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Given : • The flow rate is 0.0015 m³/s. • The density of water is 890 kg/m3. • The head loss duc to friction is 6 m The pressure on the surface is zero gauge pressure. • The · Assume the vilocity Vtop=0 m/s Choose the correct avlue of the pressure P1 (2) (1) P1
A venturi meter, shown in Fig. designed constriction whose pressure difference is a mea- sure of the flow rate in a pipe. Using Bernoulli's equation for steady incompressible flow with no losses, show that the flow rate Q is related to the manometer reading h by is a carefully 2gh(PM – p). A2 VT- (D/D;)4 where py is the density of the manometer fluid. 2
To find: H (total head) P (total pressure) Q (volumetric flow rate) m (mass flow rate) N (power) Re (Reynolds number)
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- Energy equation For steady incompressible flow for one Inlet and one outlet system Power form: W A In terms of Heads: P A P.X 2g sh mgh, POR.. Reynolds Number Re= Power = mass flux g hight: = mgh Wigh P Inertial forces V.,D Viscous forces P D. - Formula sheet 44, Cross sectional are P Print 2100 Res 4000 +α +²₂++h₂ VDpVD Flow in circular pipes Re 2300 laminar flow transitional flow Re 4000 turbulent flow 2x " +1+E₁ Determine: a. The length of segment B (La). b. The total pressure drop (pi-P2). Ch Welke PD Levve Aut L = 250 m O Correction Factor: o Laminar pipe flow : a = 2 o Turbulent flow in a pipe: a = 1 150 m с Beter Au Question 1 For the horizontal series-parallel system of the figure below, all pipes are 7 cm diameter asphalted cast iron (r= 0.12 mm) filled with water at 20°C (- 998 kg/m', -0.001 kg/m.s). The total flow rate is Q-0.0269 m/s, the lengths of segments A and Care LA-250 m and Le - 150 m, and velocity in segment A is l'A- 2.04 m/s. Neglect all minor losses. A (hem 2…
G1/ In the fig.shown, the Flow rate Pipe (A) is equal ( QA = 25 Lit15), the diameter is equal ( DA = 75 mm, D, = De = Dc =30mm), and the velocity in Pipe (D) is equal (Uo=5 m/s), the relation between flow rate in in 6o mm, Pipe (B) and pipe (c) GB =3 Qc. Find the Value of '. Re, Qc, Qo. 2- UA, UB, Uc: Pe = 30 mm water Pc = 30mm imput QA = 25 2i+/sec OA= 75 mm = 6o mm input = A outPut = B, C, D accumulation = o.
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Calculate the available net positive section head NPSH in a pumping system if the liquid density p 1200 kg/m'. The liquid dynamic viscosity u 0.4 Pa.s, the mean velocity a= 1 m/s, the static head on the suction side z = 3m, the inside pipe diameter di, = 0.0526m. the gravitational acceleration g = 9.81 m/s, and the equivalent length on the suction side EL, = 5.0 m. The liquid is at its normal boiling point. Neglect entrance and exit 1 losses.
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As6. N=35 N2=16 N3=16

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NPT Water на √5-77 P₁ = 300 kPa T₁ = 20°C d=50mm Find: M- total head; p- total pressure. Q- Volumetric flow vate m-mass flow rate N - paver Re-Reynold's number