500 lb/ft 2 20 ft 20 ft k = 4000 lb/in. 3 3 E = 1.6 × 106 psi I = 100 in.

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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500 lb/ft
2
20 ft
20 ft
k = 4000 lb/in.
3
3
E = 1.6 × 106 psi
I = 100 in.
Transcribed Image Text:500 lb/ft 2 20 ft 20 ft k = 4000 lb/in. 3 3 E = 1.6 × 106 psi I = 100 in.
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