7:22File DetailsEMA202: Dynamics (001) FA...D9914WExample 1. Person A is trying to keep his balance while ona sled B that is sliding down an icy incline. Letting mд = 78kg and m = 25 kg be the masses of A and B respectively,and assuming that there is enough friction between A andB for A not to slide with respect to B, determine the valueof the normal reaction force between A and B as well asthe magnitude of their acceleration if 0 = 20°. Frictionbetween the sled and the incline is negligible.ABiceᎾ [WExample 2. The double pendulum shown consists oftwo particles with masses m₁ = 7.5 kg and m₂ = 12 kgconnected by two inextensible cords of length L₁ = 1.4m and L2 = 2 m and negligible mass. If the system is◄ PreviousNext ‣6DDashboard CalendarTo Do NotificationsInbox

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Answered: 7:22 File Details EMA202: Dynamics…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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2. A 20 kg box sitting on a horizontal surface is pulled by a horizontal force of 64 N. The coefficient of kinetic friction between the box and the surface is 0.2. (Draw free-body diagram here) vsebn lognA en MOIT ANIMAX MATUM70038 blow 10 ode no tos 2010 Owl I 02 sa 0£to shingem seer sosot toriso 21 to obutingam and count onOno gol a. What is the normal force acting on the box?ib et bas 1910 marsib vbod-seil wai(1) b. What is the force of kinetic friction acting on the box? od no oond ton silt ei tad s c. What is the acceleration of the box? rss sdr to noitestsson sdt at tod in
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Hello. Answer is s=0.42m (how far the spring goes down before stopping the object falling). I am uploading this question as the example answer's working out was bad I find it hard to follow. I would like to see working out how the calculations equate to the answer being s=0.42m
In the above system with frictionless pulleys, 45 lb and W weights are hung on both sides. What must the weight W be in order for the 300 lb block to overcome the μ friction force and move on?
F m1, m2 two blocks connected by a spring.png Two blocks are connected by an ideal spring on a frictionless floor as shown above. Force F is applied to the block with mass m2. If k is the spring constant, x=|L-Lol is the amount of the stretch/compression of the spring, and g is the free fall acceleration, what is a correct equation for the magnitude of the net force acting on block m2? Check all what applies. m1 F(1 - :) mi+m2 O F-m2a m2 F(1 mi+m2 O (m1+m2)a F-kx
Q.6 A body of weight 120N rest on a rough horizontal surface (µ = 0.3) and is pulled by a force applied at an any of 30° to the horizontal. The force (in N) required to just cause body to slide over surface about is A 22.5 B в 27 WRONG C 35.43 D 40
A 0.150 kg frame, when suspended from a coil spring, stretches the spring 0.0400 m. A 0.200 kg lump of putty is dropped from rest onto the frame from a height of 30.0 cm (Fig.). Find the maximum distance the frame moves downward from its initial equilibrium position.
A crate of 69 kg simply stands on the moving cart with constant acceleration a. The height from the center of gravity to the cart, L, is 1.4 m, and the angle = 13°. What is the maximum acceleration a (in m/s²) the cart can have without sliding on the cart? The coefficient of static friction between the crate and the cart is μl g = 0.51. Please pay attention: the numbers may change since they are randomized. Your answer must include 3 places after the decimal point. Take g = 9.81 m/s². 0.5 m 0.5 m L Your Answer: Answer G
Search 6:00 PM Fri Feb 10 2. DETAILS MY NOTES A block of mass 2.35 kg is pushed up against a wall by a force P that makes an angle of 50.0° angle with the horizontal as shown below. The coefficient of static friction between the block and the wall is 0.221. Use g=9.8 m/s², P max! (a) Determine the possible values for the magnitude of P that allow the block to remain stationary. (If there is no maximum, enter NONE in that answer blank.) Pmin N N (b) What happens if IP has a larger value than P max!? The block slides up the wall. The block does not slide along the wall. The block slides down the wall. www webassign.net What happens if IP has a smaller value than Pmin!? The block slides up the wall. 67% The block does not slide along the wall. The block slides down the wall. PRACTICE ANOTHER
3) A thin rod of mass m and length / is balancing vertically on a smooth horizontal surface. The rod is disturbed slightly and falls to the right. Using the angle between the ground and rod as your generalized coordinate, derive the equations of motion using both the Newton-Euler approach (F=ma) and Lagrange's equations. Show that the solutions are the same. Answer: m,l 1 m1² (3cos²0 + 1)-ml²6² cosesine +mglcose = 0 rod
A crate of 67 kg simply stands on the moving cart with constant acceleration a. The height from the center of gravity to the cart, L, is 1.2 m, and the angle = 12°. What is the maximum acceleration a (in m/s²) the cart can have without tipping over on the cart? The coefficient of static friction between the crate and the cart is μg = 0.55. Please pay attention: the numbers may change since they are randomized. Your answer must include 3 places after the decimal point. Take g = 9.81 m/s². 0.5 m 0.5 m L Your Answer: ● 0 Answer G
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