Please show clear solutions As a test, CJ played croquet with a 0.922-kg. mallet head and you can assumethat it can be modelled as a point mass for simplified analysis only in this case. Meanwhile, the mallet's handle has a length of 0.95 m and a mass of 0.63 kg. Shelifts the mallet from the ground and swings it down, pivoting around her grasp, to strike the croquet ball. The ball, which is initially at rest, weighs 0.42 kilogramsand it has linear velocity of 1.995 meters per second to the right immediately after impact.A.AC.1. Which of the following is the most ideally constructed momentum-impulse diagram for the system of croquet ball and mallet together?BTARWMAVAMAVAAB0.95 mGmBVBMABVGSMABVGA SB+BRyAtABRx AtRyAtRx AtA S= TABW'||BMAVAEASMAVAmBVBBMABVGGmsv'sMABVGASmsv'sB.D.BB£· L ·MABVG+TABW'ABWA SA SMAVAMAVAR, AtBRx At+14ATABWMAVAGMABVGSA=BMAVAASTABW' GMABVGMABVGASmsv'smsv's As a test, CJ played croquet with a 0.922-kg. mallet head and you can assumethat it can be modelled as a point mass for simplified analysis only in this case. Meanwhile, the mallet's handle has a length of 0.95 m and a mass of 0.63 kg. Shelifts the mallet from the ground and swings it down, pivoting around her grasp, to strike the croquet ball. The ball, which is initially at rest, weighs 0.42 kilogramsand it has linear velocity of 1.995 meters per second to the right immediately after impact.0.95 mA. 0.475v_G = WB. 0.950v_G = wC. V_G = 0.950wD. V_G = 0.475wB1a. Which of the following momentum equations about B is CORRECT for the system of the croquet ball and mallet?A. 0.950mAVA +0.475mABVG + IABW = 0.950mÃv₁ +0.475mABVG + IABW' +0.950msv'sB. 0.950mAVA +0.475mABVG 0.950mAv +0.475mABVG+0.950m.sv's=AC. 0.950mAVA +0.475m ABVG + IABW = 0.950mAVA +0.475mABVG + IABW' +msv'sD. 0.950mAVA +0.475m abvg = 0.950mдv₁ +0.475mABVG +msv's1b. Which of the following gives the CORRECT kinematic relationship relating the velocity of the mass center of mallet handle AB VG and its angular velocity w?

Answered: Image /qna-images/answer/36967938-5323-480d-922a-02ee2d0eb27d.jpg

1a. Which of the following momentum equations about B is CORRECT for the system of the croquet ball and mallet? A. 0.950mAVA +0.475mABUG + IABW = 0.950mAVA +0.475m ABVG+IABW +0.950msv's B. 0.950mAVA + 0.475mABVG = 0.950mAv₁ +0.475m ABG +0.950msv's C. 0.950mAVA +0.475m ABVG+IABW= 0.950mAVA +0.475mABVG+IABW + msv's D. 0.950mAVA +0.475m ABVG = 0.950mAv₁ +0.475mABUG +msv's

1a. Which of the following momentum equations about B is CORRECT for the system of the croquet ball and mallet? A. 0.950mAVA +0.475mABUG + IABW = 0.950mAVA +0.475m ABVG+IABW +0.950msv's B. 0.950mAVA + 0.475mABVG = 0.950mAv₁ +0.475m ABG +0.950msv's C. 0.950mAVA +0.475m ABVG+IABW= 0.950mAVA +0.475mABVG+IABW + msv's D. 0.950mAVA +0.475m ABVG = 0.950mAv₁ +0.475mABUG +msv's

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Concept explainers

Conservation of Energy

In physics, the rule of the conservation of energy states that energy doesn’t disappear from the atmosphere; instead, it changes its form from one type to another. Energy is one of the most important physical quantities in nature, and it cannot be created or destroyed — only transformed.

Question

Please show clear solutions

As a test, CJ played croquet with a 0.922-kg. mallet head and you can assume
that it can be modelled as a point mass for simplified analysis only in this case. Meanwhile, the mallet's handle has a length of 0.95 m and a mass of 0.63 kg. She
lifts the mallet from the ground and swings it down, pivoting around her grasp, to strike the croquet ball. The ball, which is initially at rest, weighs 0.42 kilograms
and it has linear velocity of 1.995 meters per second to the right immediately after impact.
A.
A
C.
1. Which of the following is the most ideally constructed momentum-impulse diagram for the system of croquet ball and mallet together?
B
TARW
MAVA
MAVA
A
B
0.95 m
G
mBVB
MABVG
S
MABVG
A S
B
+
B
RyAt
A
B
Rx At
RyAt
Rx At
A S
= TABW'
||
B
MAVA
EAS
MAVA
mBVB
B
MABVG
G
msv's
MABVG
AS
msv's
B.
D.
B
B
£· L ·
MABVG
+
TABW'
ABW
A S
A S
MAVA
MAVA
R, At
B
Rx At
+14
A
TABW
MAVA
G
MABVG
S
A
=
B
MAVA
AS
TABW' G
MABVG
MABVG
AS
msv's
msv's

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