Engineerin Engineerin Engineerin EngineeringgggstrainStressstressstrain(in./in.)(in./in.)(ksi)(ksi)00760.08300.001750.10550.002730.12600.005690.14680.01650.16720.02560.18740.0451(Fracture)0.19750.06Plot the data as engineering stress (MPa) versus engineering strain (mm/mm) anddetermine the ultimate strength of the steel

Step 1: Analysis of the Data Table introduces the engineering stress in MPa and strain in mm/mm. The…

Answered: Engineerin Engineerin Engineerin…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

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6. The following data were collected from a 12-mm diameter test specimen of magnesium (lo = 30.00 mm). After fracture, the total length was 32.61 mm and the diameter was 11.74 mm. Load (N) Al (mm) 0.0000 5,000 10,000 15,000 20,000 25,000 26,500 0.0296 0.0592 0.0888 0.15 0.51 0.90 1.50 (maximum load) 2.10 2.79 (fracture) 27,000 26,500 25,000 a) Plot the data as engineering stress versus engineering strain. b) Compute the modulus of elasticity. c) Determine the yield strength at a strain offset of 0.002. d) Determine the tensile strength of this alloy. e) What is the approximate ductility, in percent elongation? f) Compute the modulus of resilience. g) Compute from the data and plot true stress versus true strain diagram.
Cyclic Stresses (Fatigue); The S-N Curve 4. The fatigue data for a ductile cast iron are given as follows: Cycles to Failure Stress Amplitude [MPa (ksi)] 248 (36.0) 236 (34.2) 224 (32.5) 213 (30.9) 201 (29.1) 193 (28.0) 193 (28.0) 193 (28.0) 1 × 105 3 x 105 1 x 10⁰ 3 x 106 1 x 107 3 x 107 1 108 3 × 108 (a) Make an S-N plot (stress amplitude versus logarithm cycles to failure) using these data. (b) What is the fatigue limit for this alloy? (c) Determine fatigue lifetimes at stress amplitudes of 230 MPa (33,500 psi) and 175 MPa (25,000 psi). (d) Estimate fatigue strengths at 2 × 105 and 6 × 106 cycles.
The following curve is a result of a tensile test. The gauge length was 2 in, and the specimen diameter was 0.505 in The fracture area was round with a diameter of 0.391 in. Remember to com 20000 Force (pounds force) 15000 10000 5000 0 16. The yield strength is 0 0.2% O 80,000 pl O 12.000 p 060,000 pl 85,000 p 0.1 0.2 Extension (inch) 0.3 0.4
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7. The following data were collected from a 20-mm diameter test specimen of a ductile cast iron (lo = 40.00 mm). After fracture, the total length was 47.42 mm and the diameter was 18.35 mm. Load Al (N) (mm) 0.0000 25,000 0.0185 50,000 75,000 90,000 105,000 120,000 131,000 0.0370 0.0555 0.20 0.60 1.56 4.00 (maximum load) 7.52 (fracture) 125,000 a) Plot the data as engineering stress versus engineering strain. b) Compute the modulus of elasticity. c) Determine the yield strength at a strain offset of 0.002. d) Determine the tensile strength of this alloy. e) What is the approximate ductility, in percent elongation? f) Compute the modulus of resilience. g) Compute from the data and plot true stress versus true strain diagram.
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5. The following data were collected from a standard 0.505-in.-diameter test specimen of a copper alloy (initial length lo= 2.0 in.). After fracture, the total length was 3.014 in. and the diameter was 0.374 in. Load (Ib) Al (in.) 00000 3,000 6,000 0.00167 0.00333 7,500 0.00417 9,000 10,500 0.0090 0.040 12,000 0.26 12,400 11,400 0.50 (maximum load) 1.02 (fracture) a) Plot the data as engineering stress versus engineering strain. b) Compute the modulus of elasticity. c) Determine the yield strength at a strain offset of 0.002. d) Determine the tensile strength of this alloy. e) What is the approximate ductility, in percent elongation? f) Compute the modulus of resilience. g) Compute from the data and plot true stress versus true strain diagram.
Results: material iron brass aluminum copper NH VINI Discussion: vickers hardnes test Load(kg) 50 50 30 30 Diameter of trace d1 d2 0.58 0.65 0.68 0.74 0.94 0.86 0.72 0.76 d1+d2 2 VHN Kg/mm² 1- Calculate the Vickers hardness number for the previous samples and compare the results and discuss them according to the table. 2- Draw a graphic relationship between the diameter of the trace and the hardness of Vickers. 3- What is the condition for using the Vickers hardness device?
How did temperature affect the toughness of the specimens?
1. For the stress-strain curve shown below, please estimate the properties indicated. (a) Fracture Strain Please do your work on a separate sheet of paper, and put your answers in the boxes on the right. Be sure to include the proper symbol and units. Stress Strain 70 60 50 Stress (ksi) 240 30 20 10 70 0 0.000 60 50 Stress (ksi) 40 20 10 KULL 0 0.000 0.010 0.050 0.100 Strain (in/in) Stress Strain 0.020 0.030 Strain (in/in) 0.040 0.150 0.050 (b) Ultimate Tensile Stress (c) Fracture Stress (d) Proportional Limit (e) Elastic Modulus (1) Yield Stress (g) Tensile Toughness (Modulus of Toughness) (h) Modulus of Resilience
Tensile engineering stress-strain curves through failure are depicted below. Which specimen features the highest toughness? Engineering Stress, MPa 1800- 1600- 1400- 1200- 1000- 800- 600- 400- 200- Ol 0 Aluminum Alloy 2024-T81 0.04 0.08 Stainless Steel (18-8) 1340 Steel, Water-Quenched & Tempered at 370 C Magnesium 0.12 Structural Steel (Mild Steel) Engineering Strain 0.16 1340 Steel, Water-Quenched & Tempered at 370°C Aluminum Alloy 2024-T81 Structural Steel (Mild Steel) Stainless Steel (18-8) Magnesium 0.20 0.24
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