Tensile engineering stress-strain curves through failure are depicted below.Which specimen features the highest toughness?Engineering Stress, MPa1800-1600-1400-1200-1000-800-600-400-200-Ol0Aluminum Alloy 2024-T810.040.08Stainless Steel (18-8)1340 Steel, Water-Quenched& Tempered at 370 CMagnesium0.12Structural Steel (Mild Steel)Engineering Strain0.161340 Steel, Water-Quenched & Tempered at 370°CAluminum Alloy 2024-T81Structural Steel (Mild Steel)Stainless Steel (18-8)Magnesium0.200.24

Tensile engineering stress-strain curves through failure are depicted below.Which specimen features…

Answered: Tensile engineering stress-strain…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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A tensile test for a copper specimen has been performed and the following data are obtained. - Percentage of Elongation = 61 % - Percentage of Reduction in Area = 43 % - Final length after fracture = 34.8 mm - Final Diameter after fracture = 4.2 mm & - Ultimate stress = 433 MPa Determine the Initial length, Initial diameter and Maximum load. SOLUTION: i) Initial Length (in mm) = Answer for part 1 ii) Final Area (in mm2) = Answer for part 2 iii) Initial Area (in mm2) = Answer for part 3 iv) Initial Diameter (in mm) = Answer for part 4 v) Ultimate Load (in N) = Answer for part 5
A soft steel specimen has a BHN of 150, find the equivalent 29 tensile strength in MPa. A. 393 B. 503 C. 443 D. 533 What is the value of strain at yield point of 1-inch diameter C1030 as rolled steel in the stress-strain curve? A. 0.0012 B. 0.0015 C. 0.0017 D. 0.0022 A copper column of annular cross section has an outer diameter of 0.5 m. and is subjected to an axial loading of 5 kips. The allowable compressive stress is 2 ksi. Compute the wall thickness. A. 1.15 m B. 2m C. 0.8 m D. 1 m
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The diagram shows a plot from an uniaxial test of an unknown metal. The uniaxial tensile test specimen had an original cross-sectional radius of 3.0 mm, an initial gauge length of 42 mm. At failure, the cross-sectional radius was 1.2 mm. Determine the yield strength of the unknown metal and the true stress at failure.
Mild steel 1 Young;s modulus 1219.5 Yield strain and stress (0.4101,500.08) Failure stress and strain :not able to find because the given data shows the experiment did not reach the failure point. if the material stress and strain does not reach a failure point ,what dose it means , does it means that the material is more stronger?
QUESTION 1 Predict the fatigue strength (ksi) at N=1000 cycles for a fatigue test specimen of a steel whose tensile strength is 125 ksi
Q1. (i) Initial strain Please enter your supplied question data Q1. (ii) Eo B (hr¹Pa-¹) n IVICUITO Fracture 0.003 Please enter your answers here Your Q1. (i) Answers: 4.60E-34 Q1. (ii) 3.2 Q2. o (Pa) σo (Pa) 780,000,000 Q3. t (hr) Q2. A component is made from a metal that is known to be viscoelastic and behaves according to a secondary creep rate equation with constants of B and n provided as your input values. If the component is subjected to a constant force that results in the initial strain of E provided to you, determine the design stress for a secondary creep life of 1,000 hrs before attaining a limiting strain, &, of 0.01. Q3. If the same component is subjected to a constant displacement that results in the value of initial stress, o, provided to you, calculate the time for the stress to reduce to 200MPa. Young's modulus of the bolt is E = 200GPa.
This subject is strength of materials show complete and clear solution with free body diagram and pressure diagram DONT SHORTCUT THE SOLUTION THANK YOU
1- The ultimate tensile strength of metallic sample is equal to which of the following values? If that the initial and final radius are (0.256in.) and (0.157in.) respectively. The failure occurs at maximum weight of (84*10 gm)? What is behavior type of sample? 559*10 (N/m2), as brittle behavior 620*10 (N/m2), as brittle behavior 620*10(N/m?), as ductile behavior 560MPA, as brittle behavior
200 stress 150 (MPa) 100 50 0.1 0-2 strain From the tensile stress-strain behavior for the brass specimen the diameter is 12-8 mm Calcalate the folluwing:- %3B 1- The Yield stress. 2-Modulus of elasticity. 3 - The Tensile strength.
9-Brittle failure of polycrystalline material is always associated with the intergranular crack propagation mechanism. Group of answer choices True False

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