5.2 d=67 mm.₁ = 1660 rad/s, w₂ = 3017 rad/s.=985.3 rad/s, w₂ = 2949 rad/s.1153 rad/s, w,5.35.45.55.6=1703 rad/s.1521.6 rad/s, ₂ = 432.8 rad/s.5.7 482.3 rad/s.5.874mm.5.9 No unique solution.5.10 58mm. A 22.63 kg compressor impeller wheel is driven by a 13.56 kg turbine mounted on a common shaft(see Figure 1.3) manufactured from steel with Young's modulus E = 207 GN/m2. The design speedis 10 000 rpm.Determine the shaft diameter so that the first critical speed is 12 000 rpm giving a safety marginof 2000 rpm.Use Rayleigh's equation and assume rigid bearings and a massless shaft.Compressor impellerBearing0?BearingTurbine254 mm254 mm254 mmFigur 1.3: Turbine shaft.

Answered: 5.2 d=67 mm. ₁ = 1660 rad/s, w₂ = 3017…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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A 6-in-wide polyamide F-1 flat belt is used to connect a 4-in-diameter pulley to drive a larger pulley with an angular velocity ratio of 3. The center-to-center distance is 8 ft. The angular speed of the small pulley is 1850 rev/min as it delivers 2 hp. The service is such that a service factor Ks of 1.25 is appropriate. (a) Find Fc, Fi, F1a, and F2. (b) Find Ha, nfs, and belt length. (c) Find the dip.
A flat belt is to consist of 2 m diameter and 1.5 m diameter cast iron pulleys spaced at 4.8 m apart. It is to transmit 50 kW at a pulley speed of 380 rev/min. By using a service factor of 1.1 and a design factor 1277 ks 60 of 1.0: (a) Calculate the hoop tension, F. due to centrifugal force. (b) (c) b Find the torque,T due to the design power and pulley speed. Design and select a suitable belt type and dimension for the above application.
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The diameter of shaft is 45mm. Compare the shear stress in the key to the torque in the shaft. calculate the key size to use for the 15 kW low speed shaft with a speed of 384 rpm. Take bxb = 10mm x 10mm as d = 45mm L = 1.5 cm.
Q1/ A 6-in-wide polyamide F-1 flat belt is used to connect a 2-in-diameter pulley to drive a larger pulley with an angular velocity ratio of 0.5. The center-to-center distance is 9 ft. The angular speed of the small pulley is 1750 rev/min as it delivers 2 hp. The service is such that a service factor Ks of 1.25 is appropriate. (a) Find Fc, Fi, Fla, and F2. (b) Find Ha, nfs, and belt length. (c) Find the dip.
In the figure below is a proposed shaft design. The shaft is designed with a motor attached to the overhang (right side) with a flexible coupling. The motor provides a torque of 2500 lbf·in at a speed of 1200 rpm. A spur gear with a 20° pressure angle and a pitch diameter of 4 in is located at the key seat in between the two bearings and supposed to transmit the power out. A ball bearing and cylindrical bearing are planned for the left and right support respectively. Determine the minimum fatigue factor of safety by evaluating at any critical locations. Use the DE-ASME Elliptic fatigue criterion. Compute the deformation using an approximated shaft of 1.875 in uniform diameter and determine if it has adequate rigidity by comparing against the number given in Table 7-2.
I want right solution plz solve if you know 100% flange coupling connects two 50 mm diameter lengths of commercial shafting. The coupling flanges are bolted together with four bolts of the same material as the shaft. The bolts are set in clearance holes. The diameter of the bolt circle is 240 mm and the flange thickness is 22 mm, Determine the minimum bolt diameter required to transmit the same torque that the shaft can transmit. What power may be transmitted at 200 rev/ min under steady load conditions?
Hi pls help me with the solutio. Of this problem exercise. The answer is already attached in bold. your will would be much appreciated

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