Problem 4 For the 6 bar Watt's mechanism shown below, the link lengths are as follows: O2A = 1, AB = 1.2, 0204 = 2, 04B = 2, 0406 = 1.9, 06D = 2.4, CD = 1. Also O4C = 04B = BC. The input angle is 02. For 02 = 45 degrees, find the positions of the moving pivots A, B, C, and D in the global coordinate system YO2X. 0406 makes an angle of -30 degrees with the horizontal axis. [25 points] C Y R6 B D R3 A R5 R4 R7 X R2 RI Rs 04 02 06 Figure 4: Watt's mechanism

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
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Problem 4
For the 6 bar Watt's mechanism shown below, the link lengths are as follows: O2A = 1, AB = 1.2,
0204 = 2, 04B = 2, 0406 = 1.9, 06D = 2.4, CD = 1. Also O4C = 04B = BC. The input
angle is 02. For 02 = 45 degrees, find the positions of the moving pivots A, B, C, and D in the
global coordinate system YO2X. 0406 makes an angle of -30 degrees with the horizontal axis.
[25 points]
C
Y
R6
B
D
R3
A
R5
R4
R7
X
R2
RI
Rs
04
02
06
Figure 4: Watt's mechanism
Transcribed Image Text:Problem 4 For the 6 bar Watt's mechanism shown below, the link lengths are as follows: O2A = 1, AB = 1.2, 0204 = 2, 04B = 2, 0406 = 1.9, 06D = 2.4, CD = 1. Also O4C = 04B = BC. The input angle is 02. For 02 = 45 degrees, find the positions of the moving pivots A, B, C, and D in the global coordinate system YO2X. 0406 makes an angle of -30 degrees with the horizontal axis. [25 points] C Y R6 B D R3 A R5 R4 R7 X R2 RI Rs 04 02 06 Figure 4: Watt's mechanism
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