What is the BM value at x=6m from A? (in kNm to 1 d.p.) 40 kN A 2m B 6m 120 kN с 2m D
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What is the Bending moment value at x=6m from A?
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- Please show how to get answerA X₁ RA P₁ X₂ P₂ 2 X3 X L 10 C ХА B RB 22 Z P₁ = 30kN; P₂ = 50kN; w= 10kN/m; L = 6m x₁ = 1m; x₂ = 2m; x3 = 3m; x = 5m Find RA and Rg, and draw SFD and BMDA bracket is riveted to a column by 6 rivets of equal size as shown in Fig. It carries a load of 100 kN at a distance of 250 mm from the column. If the maximum shear stress in the rivet is limited to 63 MPa, find the diameter of the rivet.
- antuitive methodology (seize and fox) noting they will be different. olowing cases, find the degrees-of-freedom using KMOGE (Identify L. h. Jz and M) and using the em 3: KMOGE has conditions under which it simply produces the wrong answer. In each of the A. L= Mseize and Fix B L = MKMOGE = Mseize and Fix J = MEMOGE Msetze and Fixusing the information from the figure find the unknowns ( ma,-y,x). (using analytical method) subject is balancing from theory of machinehello im trying to answer this now, can you help me?
- please solve ture and clearThe left side of this equation tells how much energy Q the cylinder gives to the water while it cools. The right side of this equation tells how much energy Q the water and aluminum cup absorb from the cylinder to warm up. Because it is the same energy, they are equal. What is known in this equation? Mcyl 411.7 g, malum 46.5 g, malum+water = 175 g Can you find: mwater =? g Twater = Talum = 20°C (water and cup of room temperature) 90°C, T; = 35°C (hot cylinder and cool "cylinder+cup+water" temperatures) Tcyl kCal Calum = 0.22, Cwater 1 (specific heat of water and aluminum, measured in units kg-°C What are we looking for is Ccul - How we find it? Plug all the numbers into the equation (1), Ccul will be one unknown which you can calculate from the equation. Important, convert all the masses from grams to kilograms! After you find Ccyl, compare it to known value for the copper 0.093(our cylinder is made out of copper). |Ceyl -0.093| % : · 100% 0.093TRANSCRIBE THE FOLLOWING SOLUTION IN DIGITAL FORMAT