Problem #6 The two-member frame is used to support the 150-lb weight. Determine the horizontal and vertical components of force at pins A, B, C, and D. 9 ft 4 ft- B 8 ft 3.75 ft 1 ft 1 ft
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- Problem 6 The mass of the suspended weight is 16 kg. Note that point D is the midpoint of bar BE and the connection at E is a roller support. Determine the magnitude of the force in pins B and C. Hint: Start with a FBD of the entire structure. 160 mm. 240 mm B 160 mm D 160 mm C E 160 mm. m3Calculate the forces in members BC, BE, and EF. Solve for each force from an equilibrium equation which contains that force as the only unknown. The forces are positive if in tension, negative if in compression. 3.0 m BC= Answers: BE= A 3.0 m EF= G i i i B 3.0 m 3.0 m F 1.9 m E 3.0 m 20.0 KN KN KN kN D
- Calculate the forces in members BC, BE, and EF. Solve for each force from an equilibrium equation which contains that force as the only unknown. The forces are positive if in tension, negative if in compression. 5.0 m b BC= Answers: BE= A 5.0 m EF= G i i i B 5.0 m 5.0 m C 3.4 m E 18.0 KN 5.0 m kN kN KN DCalculate the forces in members BC, BE, and EF. Solve for each force from an equilibrium equation which contains that force as the only unknown. The forces are positive if in tension, negative if in compression. 3.5 m BC= Answers: BE = A 3.5 m EF= G i i i B 3.5 m 3.5 m C 2.1 m E 3.5 m KN KN 27.0 KN kN DPROBLEM. The given frame is subjected to the applied loads of P and Q. Given: P=146.3 kN Q = 120.9 KN 0 = 41.82° 1. Draw the FBDs of all members. 2. Determine the force in each link- AF, BG, DG, and EH. Note: Neglect the weight of the members.
- FOR FULL CREDIT - DRAW A FREE-BODY DIAGRAM OF THE FRAME AND EACH MEMBER OF THE FRAME. When you write an equation indicate which body it is for. For example : "E F, = 0 for member ABC" or "E F = 0 for entire frame" Problem 1: Determine the resultant forces at pins B and C on member ABC of the four-member frame. + 2n- 150 lb/ft - 5 ft Note: B. Member FED is one solid piece. Member ABC is one solid piece. 4 ft BE and CD are two-force members. Ans. C = 350 Ib v B = 1,531 lb 53.1°Calculate the forces in members BC, BE, and EF. Solve for each force from an equilibrium equation which contains that force as the only unknown. The forces are positive if in tension, negative if in compression. 5.0 m Answers: BC- BE- A 5.0 m EF= i i i B 5.0 m 5.0 m C 20.5 KN 5.0 m 3.4 m 3 3 3 KN D8
- ENCLOSED ALL final answers on a box. (SHOW COMPLETE SOLUTION PLS)The truss system shown below is supported by a pin at A and a roller at G. Determine the value of the support reactions at A and G. Use method of joint to find forces in member GA and GF. State if these members are in tension or compression.The 48-lb rectangular access door is held in the 90° open position by the single prop CD. Determine the magnitude of the force F in the prop and the magnitude of the force normal to the hinge axis AB in each of the small hinges A and B. Assume a = 19 in., b = 40 in., c = 10 in., d = 36 in. Answers: F= A = B = i 15.9 i lb ! lb ! lb