4-e P₁ P₁₂ D 2m B 1.5 m Take P₁ = 45 kN and P2 = 30 KN. You found that BC=0KN and CD=45kN(c). Find the force of members BD and AD. Use the method of your choice (sections or joints).
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- Repeat 1.3-9 but use the method of sections go find member forces in AC and BD.I am not entierly sure where I when wrong here but I ended up getting 38.188lbs as an incorrect answer. I am pretty confident in my meathod I just belive I made an algibraic error. Could you solve this for me? thank you so much.- For the frame of the figure:a) Draw up the free-body diagram of the three elements that compose it, for the BCD element, set theequilibrium equations (summation of forces along the longitudinal axis "t" and the perpendicular "n", as well as thesummation of moments at point C). Note: it is not required to evaluate the reactions or the charges on the elements.b) Make a cut at the midpoint between C and D and “CALCUE” the internal loads numerically.
- Find the reactions. Fill in the blanks and draw the final free body diagram correctly.Previously we addressed the problem of a pinned-joint truss in the shape of a regular pentagon that is supported on rollers and loaded by a single vertical force F. We want to determine the loads in the members and the displacements of the joints. 4 F You can assume the following: 3 Since this is an equilibrium problem, it can be tackled as a virtual work problem. Also, the loads are constant, so their virtual work can be described as a change in energy. Thus the system is a conservative system. Instead of approaching the problem by writing the equilibrium equations, solve it using the minimization of energy. = 6 -E4(A)², where A = the change in length of the Note that the energy for each truss member is member, E is the modulus of elasticity for all members and A is the cross sectional area of all members. All outside members are of length L, and the interior members are determined by the geometry to be 1.61804L. Also, note that the system is symmetrical about the vertical centerline.…please explain!
- HelpA bar of steel and a bar of aluminum e the dimensions shown in the figure. Calcu- MS 52 A wall bracket is constructed as shown in the figure. All joints may be considered pin- 2-11. connected. The steel rod AB has a cross-sectional area of 5 mm². The member BC is a rigid beam. If a 1.00 m diameter frictionless drum weighing 4 500 N is placed in the position shown, what will the elongation of the rod AB be? Ans: 8.04 mm. 1.80 m -4 500 N drum 2.40 m Pinned joint PROB. 2 - 11 1.50 mPlease solve the problem step by step. Hope you know the hooke's law
- Beam AB has a pin support at A and a roller support at B Joint B is also restrained by a linearly elastic rotational spring with stiffness kR, which provides a resisting moment MBdue to rotation at B. Member AB has flexural rigidity EI. A moment M0acts counterclockwise at B. Use the method of superposition to solve for all reactions. Find an expression for joint rotation Ain terms of spring stiffness kR. What is Awhen kR 0? What is Awhen kR— ? What is Awhen kR= 6EI/L?Find support reactions at 4 and Band then use the method of joints to find all member forces. Let b = 3 m and P = 80 kN.A polyethylene tube (length L) has a cap that when installed compresses a spring (with under-formed length L1) by an amount ?? = (L1 = L). Ignore deformations of the cap and base. Use the force at the base of the spring as the redundant. Use numerical properties given in the boxes. (a) What is the resulting Force-in the spring, Fk? (b) What is the resulting Force in the tube, Ftl (c) What is the filial length of the tube, Lf? (d) What temperature change ?T inside the tube will result in zero force in the spring