4-eP₁P₁₂ D2mB1.5 mTake P₁ = 45 kN and P2 = 30KN. You found that BC=0KNand CD=45kN(c). Find theforce of members BD and AD.Use the method of your choice(sections or joints).

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Answered: 4-e P₁ P₁₂ D 2m B 1.5 m Take P₁ = 45 kN…

Mechanics of Materials (MindTap Course List)

9th Edition

ISBN:9781337093347

Author:Barry J. Goodno, James M. Gere

Publisher:Barry J. Goodno, James M. Gere

Chapter11: Columns

Section: Chapter Questions

Problem 11.3.10P: Repeat Problem 11.3-9. Use two C 150 × 12.2 steel shapes and assume that E = 205 GPa and L = 6 m.

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Repeat 1.3-9 but use the method of sections go find member forces in AC and BD.
3. 2 ft 1106 2 ft B ww Cord AB is 2 ft long, the force P = 76 lb, the angle 0 = 56 degrees and the spring's stiffness is k = 56 Ib/ft.
Q1
Solve correct by hand please
I am not entierly sure where I when wrong here but I ended up getting 38.188lbs as an incorrect answer. I am pretty confident in my meathod I just belive I made an algibraic error. Could you solve this for me? thank you so much.
IMPORTANT NOTE: PLEASE ANSWER PART 2 ONLY!! Answer in part 1: 2950.23N
Multiple answers are allowed
Previously we addressed the problem of a pinned-joint truss in the shape of a regular pentagon that is supported on rollers and loaded by a single vertical force F. We want to determine the loads in the members and the displacements of the joints. 4 F You can assume the following: 3 Since this is an equilibrium problem, it can be tackled as a virtual work problem. Also, the loads are constant, so their virtual work can be described as a change in energy. Thus the system is a conservative system. Instead of approaching the problem by writing the equilibrium equations, solve it using the minimization of energy. = 6 -E4(A)², where A = the change in length of the Note that the energy for each truss member is member, E is the modulus of elasticity for all members and A is the cross sectional area of all members. All outside members are of length L, and the interior members are determined by the geometry to be 1.61804L. Also, note that the system is symmetrical about the vertical centerline.…
2..Assume that the cable GBH is replaced by a cable GB only (TBH-0). So the frame ACD is supported by ball-and-socket joints at A and D and by the cable GB. You know that the frame supports at C a load of magnitude of 268 N. Find the tension in the cable GB. CopMan se reared for praticion or decay 0.925 m 0.35 m 0.5 m 0.5 m 0.875 m H 0.75 m 0.75 m
please explain!
x=8
Please solve this question with all details please (handwritten) I will give like if it’s correct

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4-e P₁ P₁₂ D 2m B 1.5 m Take P₁ = 45 kN and P2 = 30 KN. You found that BC=0KN and CD=45kN(c). Find the force of members BD and AD. Use the method of your choice (sections or joints).