Three distributed loads act on a beam as shown. The loadbetween A and B increases linearly from 0 to a maximumintensity of w₁ = 14 lb/ft at point B. The load then varieslinearly with a different slope to an intensity of w₂ = 18.6W2lb/ft at C. The load intensity in section ✓ of the beam isconstant at W3 = 11.2 lb/ft. For each load region, determinethe resultant force and the location of its line of action(distance to the right of A for all cases).BY NC SA2016 Eric DavishahlWIB-b-W2W3Values for dimensions on the figure are given in the followingtable. Note the figure may not be to scale.Variable Valuea7.60 ftb14.4 ftC7.60 ftThe resultant load in region is F =nilb and actsft to the right of A.The resultant load in region BC is FR2 =lb and actsft to the right of A.The resultant load in region CD is FR3lb and acts=ft to the right of A.

Step 1:Segment AB: Length LAB=7.60 ftUniform varying load from w1=0 lb/ft at A to w1=14 lb/ft at…

Answered: Three distributed loads act on a beam…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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The simply supported beam is subjected to the force F = 700 N and the uniform distributed load with intensity w = 150 N/m. Draw the shear force and bending moment diagrams (in your homework documentation) and determine the equations for V(r) and M(x). Take a = 0 at point A. 19 F a Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. Variable Value a 5.2 m 2.6 m 3.12 m Support Reactions The reaction at A is N. The reaction at D is N. Shear Force and Bending Moment Equations In section AB: V(x)= N and M(x)= N-m. In section BC: v(x)- N and M(x)= N-m. In section CD: V(x)- N and M(x)= N-m. A
3. Use the double integration Method and compute the value of EI at midspan for the beam loaded as shown in the figure. R₁ 6 ft 1000 lb 400 lb/ft <-3 ft →→ 4 ft3 ft R₂
Problem 2: The beam is held in equilibrium by a roller at A and a pin at B. The beam supports a uniform distributed load (2 kip/ft) and a concentrated moment (30 kip-ft) at the locations shown. Use the equation method to solve this problem. 2 kip/ft Į 5 ft 5 ft 30 kip-ft 5 ft (a) Derive expressions for V(x) and M(x) in each section of the beam. (b) Use the results from part (a) to draw the shear force (V) and bending moment (M) diagrams for the beam. Clearly label all important values and points on the diagrams.
The beam ABis attached to the wall in the zz plane by a fixed support at A. A force of F = (- 156i + 58.0j + 350k) N is applied to the end of the beam at B. The weight of the beam can be modeled with a uniform distributed load of intensity w = 65.0 N/m acting in the negative z direction along its entire length. Find the support reactions at Á. F B y а Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. Variable Value 5.80 m 5.00 m 3.80 m A = i+ j- k) N MA = k) N-m
solve the question provided in the image completely.
The beam AB in the figure supports a load which varies from an intensity of 50 KN per linear meter to 200 KN per meter. 8.2 Determine the location of the resultant load from point A. 200 KN/m 50 KN/m B 6 m
1. The cantilever beam AH is acted upon by a uniformly distributed downward load of intensity 4P/L(force/length)between A and B, a concentrated moment M-2PL at C, and a vertical force Pat D. Using P=20kN and L=1.2 m, construct the shear force and bending moment diagrams for the beam. Mark numerical values for points A through H, along with max/min values on these diagrams. 4P/L Mo L/4 L/4 L/4 L/4 A C H V(x)/P M(x)/PL
Determine the resultant of the internal loads acting on thecross section inC of the beam shown in the figure below.
The simply supported beam is subjected to the force F-600 N and the uniform distributed load with intensity w=450 N/m. Draw the shear force and bending moment diagrams (in your homework documentation) and determine the equations for V(z) and M(2). Take 2 = 0 at point A. 19 W B F 2013 Michael Swanbom BY NC SA D Χ a. -b- - Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. Variable Value α 4 m b 2 m с 3 m Determine the maximum shear force (magnitude) and its location in the beam, and the maximum bending moment (magnitude) and its location in the beam. Note: On an exam, you may be required to actually sketch the shear and moment diagrams, but there is no reasonable way to assess this on WAMAP. Maximum shear stress: Vmax Maximum bending moment: Max = N located at x = m Nm located at x = m
18KN/M D 3m 5m 1-25 m EL = Constant B Draw Bending Moment diagram after you analyze the structure using the force Method. Redundant: vertical reaction and moment at B.
Determine the maximum allowable intensity w of the uniform distributed load that can be applied to the beam. Assume w passes through the centroid of the beam’s cross-sectional area, and the beam is simply supported at A and B. The allowable bending stress is sallow = 165 MPa.
Consider the following values in the given beam above: L1=6m L2 = 2 m L3 = 4 m L4=3m L5=2 m L6=1m W1 = 90 kN/m W2 = 30 kN/m P = 50 kN M = 60 kN-m Point E is an internal hinge W1 B L2 L3 2 m E W2 L5 L6 H

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