Pg. 6 5. A body of 200 N weight rests on a horizontal plane. the coefficient of friction between the body and the plane 13. 0.25. Find the free inclined upwards at 30° to the horrzontal Which will just cause motion. W R Q = friction angle F 90-010 RA vw Vector Φ 0 = inclined angle 90-0+0 = angle between Fond R Han Q = 4 = 0.25 E = Friction angle = ton" "6.25 Sino Fricton angle = 14°2′ W sin (90-0+0) Angle opposite W = 90° -14°2′ +30=105°58′ F 200 Sin 12 sin los°58' F = 200 x 0.2425 0.9615 Ans, = 50,44 N Hilroy
Pg. 6 5. A body of 200 N weight rests on a horizontal plane. the coefficient of friction between the body and the plane 13. 0.25. Find the free inclined upwards at 30° to the horrzontal Which will just cause motion. W R Q = friction angle F 90-010 RA vw Vector Φ 0 = inclined angle 90-0+0 = angle between Fond R Han Q = 4 = 0.25 E = Friction angle = ton" "6.25 Sino Fricton angle = 14°2′ W sin (90-0+0) Angle opposite W = 90° -14°2′ +30=105°58′ F 200 Sin 12 sin los°58' F = 200 x 0.2425 0.9615 Ans, = 50,44 N Hilroy
International Edition---engineering Mechanics: Statics, 4th Edition
4th Edition
ISBN:9781305501607
Author:Andrew Pytel And Jaan Kiusalaas
Publisher:Andrew Pytel And Jaan Kiusalaas
Chapter7: Dry Friction
Section: Chapter Questions
Problem 7.50P: The block of weight W is pulled by the force P inclined at the angle to the horizontal. Find the...
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Hi,
wondering could I get an explanation for this question. (Out of a reeds book) looking for clarification on the friction angle and how to calculate it, and also why the angle is 90 minus friction angle plus inclined angle.
if your want to include a new means of these calculations or a better breakdown that is fine too. Thanks
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