A machine part made of cast aluminum has the properties Sut = 40 kpsi, Suc = 35 kpsi and ε = 0.045. A critical point in the machine part has a plane stress state shown in the sketch where σx = -4 kpsi, σy = 12 kpsi and Txy = 6 kpsi. For this critical point, (i) Determine the factor of safety using the Coulomb Mohr-theory. (ii) Plot the failure locus for the Coulomb Mohr-theory and the load line. Stress Transformation Equation: 01,2 = 2 ± 2 (2) + Txy² бу = 12 kpsi Txy = Tyx = 6 kpsi 0x = 4 kpsi
A machine part made of cast aluminum has the properties Sut = 40 kpsi, Suc = 35 kpsi and ε = 0.045. A critical point in the machine part has a plane stress state shown in the sketch where σx = -4 kpsi, σy = 12 kpsi and Txy = 6 kpsi. For this critical point, (i) Determine the factor of safety using the Coulomb Mohr-theory. (ii) Plot the failure locus for the Coulomb Mohr-theory and the load line. Stress Transformation Equation: 01,2 = 2 ± 2 (2) + Txy² бу = 12 kpsi Txy = Tyx = 6 kpsi 0x = 4 kpsi
Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter1: Tension, Compression, And Shear
Section: Chapter Questions
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
Transcribed Image Text:A machine part made of cast aluminum has the properties Sut = 40 kpsi, Suc = 35 kpsi and ε = 0.045. A critical
point in the machine part has a plane stress state shown in the sketch where σx = -4 kpsi, σy = 12 kpsi and
Txy = 6 kpsi. For this critical point,
(i) Determine the factor of safety using the Coulomb Mohr-theory.
(ii) Plot the failure locus for the Coulomb Mohr-theory and the load line.
Stress Transformation Equation:
01,2 =
2
±
2
(2)
+ Txy²
бу
= 12 kpsi
Txy = Tyx
= 6 kpsi
0x = 4 kpsi
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