The answers can be found at the end of the practice problem set, and full solutions can be discussed during tutorial time and/or office hours. 1. Ethanol (EtOH) reacts with H* and Cl to give ethyl chloride (EtCI). A possible mechanism is shown below. The first step is thought to be reversible, with rate constant k.1 corresponding to the reverse of step 1. The second step is assumed to be irreversible. Step 1: ETOH + H* 3 ETOH,+ Reverse of Step 1: EtO H,+ Et0H + H+ Step 2: EtOH,+ + Cl- 3 EtCl + H20 a) What is the overall balanced chemical equation? b) What is/are the reaction intermediate(s)? c) Using the steady state approximation, derive the general rate law for this mechanism. d) What does the general rate law simplify to if we assume step 2 is the rate determining step? 2. A chemical reaction increases in rate by a factor of 12.9 when the temperature is raised from 5.0°C to 30.0°C (all other conditions such as concentrations remain the same). Calculate the activation energy (in kJ mol-1) for this reaction. 3. What are appropriate units for the rate constant for the hypothetical rate law: rate = k[A]²[B][C]?

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The answers can be found at the end of the practice problem set, and full solutions can be discussed during
tutorial time and/or office hours.
1. Ethanol (ETOH) reacts with H* and Cl to give ethyl chloride (EtCl).
A possible mechanism is shown below. The first step is thought to be reversible, with rate constant k-1
corresponding to the reverse of step 1. The second step is assumed to be irreversible.
Step 1: EtOH + H+
k1
EtOH,+
Reverse of Step 1: E1OH,*
Et0H + H+
Step 2: Et0H,+ + Cl-
3 EtCl + H,0
a) What is the overall balanced chemical equation?
b) What is/are the reaction intermediate(s)?
c) Using the steady state approximation, derive the general rate law for this mechanism.
d) What does the general rate law simplify to if we assume step 2 is the rate determining step?
2. A chemical reaction increases in rate by a factor of 12.9 when the temperature is raised from 5.0°C to
30.0°C (all other conditions such as concentrations remain the same). Calculate the activation energy (in kJ
mol-1) for this reaction.
3. What are appropriate units for the rate constant for the hypothetical rate law: rate =
k[A]²[B][C]?
4. The decomposition of N205 in the gas phase is first order in N2O5. If the concentration of N2O5 drops from
0.200 M to 0.100 M in 14.2 minutes, how long would it take for N2O5 to drop from 0.200 M to 0.025 M?
5. The rate constant for a first order reaction is 4.60 x 10-4 s-1 at 350°C. If the activation energy is 104 kJ mol-1,
calculate the temperature at which its rate constant is 5.28 x 10-2 min1. Watch your units!
Transcribed Image Text:+ K-1 The answers can be found at the end of the practice problem set, and full solutions can be discussed during tutorial time and/or office hours. 1. Ethanol (ETOH) reacts with H* and Cl to give ethyl chloride (EtCl). A possible mechanism is shown below. The first step is thought to be reversible, with rate constant k-1 corresponding to the reverse of step 1. The second step is assumed to be irreversible. Step 1: EtOH + H+ k1 EtOH,+ Reverse of Step 1: E1OH,* Et0H + H+ Step 2: Et0H,+ + Cl- 3 EtCl + H,0 a) What is the overall balanced chemical equation? b) What is/are the reaction intermediate(s)? c) Using the steady state approximation, derive the general rate law for this mechanism. d) What does the general rate law simplify to if we assume step 2 is the rate determining step? 2. A chemical reaction increases in rate by a factor of 12.9 when the temperature is raised from 5.0°C to 30.0°C (all other conditions such as concentrations remain the same). Calculate the activation energy (in kJ mol-1) for this reaction. 3. What are appropriate units for the rate constant for the hypothetical rate law: rate = k[A]²[B][C]? 4. The decomposition of N205 in the gas phase is first order in N2O5. If the concentration of N2O5 drops from 0.200 M to 0.100 M in 14.2 minutes, how long would it take for N2O5 to drop from 0.200 M to 0.025 M? 5. The rate constant for a first order reaction is 4.60 x 10-4 s-1 at 350°C. If the activation energy is 104 kJ mol-1, calculate the temperature at which its rate constant is 5.28 x 10-2 min1. Watch your units!
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