For the proposed reaction mechanism shown below what is the overall chemical equation predicted by this mechanism and what is the rate law derived from this mechanism? Hint: The slow step determines the overall rate then see if there is a possible substitution for one of the reactant. When you get to the equilibrium reaction write the rate law in terms of [N2O5] and then substitute this back into the overall rate equation. (slow step, K1 N205 → NO2 + NO3 forward rate) (fast step, K2 forward rate) NO2 + NO3 → NO2 + O2 + NO (fast step, equilibrium, K3 forward rate, K3 = NO + N205 → 3NO2
For the proposed reaction mechanism shown below what is the overall chemical equation predicted by this mechanism and what is the rate law derived from this mechanism? Hint: The slow step determines the overall rate then see if there is a possible substitution for one of the reactant. When you get to the equilibrium reaction write the rate law in terms of [N2O5] and then substitute this back into the overall rate equation. (slow step, K1 N205 → NO2 + NO3 forward rate) (fast step, K2 forward rate) NO2 + NO3 → NO2 + O2 + NO (fast step, equilibrium, K3 forward rate, K3 = NO + N205 → 3NO2
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![For the proposed reaction mechanism shown below what is the overall chemical equation predicted
by this mechanism and what is the rate law derived from this mechanism? Hint: The slow step
determines the overall rate then see if there is a possible substitution for one of the reactant.
When you get to the equilibrium reaction write the rate law in terms of [N205] and then substitute
this back into the overall rate equation.
(slow step,
K1
N205 → NO2 + NO3
forward
rate)
(fast step,
K2
NO2 + NO3 → NO2 + O2 + NO
forward
rate)
(fast step,
equilibrium,
K3
NO + N205
3NO2
forward
rate, K_3
reverse](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff858bc17-399e-4de1-b51d-729161116f8a%2F84f6a1b3-2fce-4117-b7de-297a8034225f%2Fhqu58ikf_processed.png&w=3840&q=75)
Transcribed Image Text:For the proposed reaction mechanism shown below what is the overall chemical equation predicted
by this mechanism and what is the rate law derived from this mechanism? Hint: The slow step
determines the overall rate then see if there is a possible substitution for one of the reactant.
When you get to the equilibrium reaction write the rate law in terms of [N205] and then substitute
this back into the overall rate equation.
(slow step,
K1
N205 → NO2 + NO3
forward
rate)
(fast step,
K2
NO2 + NO3 → NO2 + O2 + NO
forward
rate)
(fast step,
equilibrium,
K3
NO + N205
3NO2
forward
rate, K_3
reverse
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