Rate Constant k. Some measurements of the initial rate of a certain reaction are given in the table below.[N2][H2] initial rate of reaction1.21 M 1.70M0.102 M/s0.359 M 1.70 M0.00898 M/s1.21M 0.464 M0.00760 M/sUse this information to write a rate law for this reaction, and calculate the value of the rate constantRound your value for the rate constant to 2 significant digits. Also be sure your answer has the correrate =k ==0Check1!k]x100.0+9Start over5F1F280a01F3F4@12$%5S4#3MacBook Air해요F5F666&277

Step 1: The rate law expression of the given reaction is: rate = k [N2]m[H2]n…

Answered: Some measurements of the initial rate…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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3. The reaction H₂SO3(aq) + 6(aq) + Haq) → Se(s) +213(aq) + 3H₂0 (1) was studied at 0°C. The following data were obtained: Experiment # 1 2 3 4 5 6 7 [H₂SO3(aq)lo (mol/L) constant? 1.0 x 104 2.0 x 10-4 3.0 x 104 1.0 x 10-4 1.0 x 10-4 1.0 x 104 1.0 x 104 [¹] (mol/L) 2.0 x 10² 2.0 x 10-² 2.0 x 10-² 4.0 x 10-² 1.0 x 10-² 2.0 x 10-² 1.0 x 10-² Find the order of the reaction with respect to [H₂SO3]. respect to [I-¹]. reaction with respect to [H+¹]. is the overall order of the reaction? Find the value of the rate constant (k). Only write the number. [H¹+] (mol/L) 2.0 x 10-² 2.0 x 10-² 2.0 x 10-² 2.0 x 10-² 2.0 x 10-² 4.0 x 10-² 4.0 x 10-² Rate (mol/L.s) Find the order of the reaction with Find the order of the What What are the units of the rate 1.66 x 10-7 3.33 x 10-7 4.99 x 10¹7 6.66 x 10-7 0.42 x 10-7 13.2 x 10-7 3.36 x 10-7
Draw the energy diagram (energy verses course of reaction curve) for the reaction 4 PH3 + 2 H2 + 9 O2 <–> 2 P2O5 + 8 H2O(liq) + 25 kJ
DETERMINATION OF A,H FOR THE REACTION OF Mg AND HCl Minimize D The results from one run are shown below. 40 00003333333t1&C66C0000000000333333113ttteeccc000000 y = -0.51215 x + 40.274 20 10 4 5 Time (min) Q3 Use the graph to determine Tinitial and Tfinal. You must then use these values to calculate the change in temperature for the reaction. Tinitial (°C) Tinal (°C) AT (°C) 1 2 Temperature (°C) 30
3. The following reaction: A' (a) + B (ag + C (an)→ G* (ae) +2 H ) AH = -250 kJ There are two proposed mechanism: Mechanism 1 A' () + B aa) AB' a) + D (a) Step 1 AB" (a) (fast) + E (a) + Hm → G' sae) + H ) + D² (n) Step 2 (slow) Step 3 E (agi+ C (a) (fast) Mechanism 2: Step 1 AB' (a) A' (an) + B (ag) AB' (a) + C ja) (fast) Step 2 + G' (a) + 2 H() (slow) The reactions was determined to have the following rate law: r= k[A'][B] a) Which of the two proposed mechanisms is valid? Explain. b) List any reaction intermediates: catalysts: c) What is a rate determining step? d) If the activation energy for the overall forward reaction is 150 kJ, sketch the potential energy diagram for the above reaction; showing the overall reaction, the reaction mechanism, labelling the AHu, AHy, Eapu, Eag, reaction intermediates, and activated complex. rvs fwd drvs/
we now have: Step 1: Fast, reversible HA = H+ + A- Step 2: Fast, reversible X + H+ = HX+ Step 3: Slow HX+ = productsrate= k3 k2/k-2 [X][HX+] Does the current rate law contain an intermediate?
Ethyl acetate reacts with sodium hydroxide when the two are mixed. The reaction, called ester hydrolysis, yields products ethyl alcohol and sodium acetate. The equation is CH3CO₂C₂H5(aq) + NaOH(aq) --> C₂H5OH(aq) + CH3CO₂Na(aq) The following data were obtained: Initial Concentration of CH3CO₂C₂Hs (mol L-¹) Initial Concentration of NaOH (mol L-¹) 0.005 0.010 0.005 0.010 0.020 0.020 The rate law for this reaction is: O Rate-k[CH3CO₂C₂H5]²[NaOH] O Rate-k[CH3CO₂C₂H5] + [NaOH] O Rate-k[CH3CO₂C₂H5]²[NaOH)² O Rate-k[CH3CO₂C₂H5] [NaOH] Initial Rate of Formation of C₂H5OH (mol L-1¹) 5.40 x 10-6 2.16 x 10-5 1.08 X 105
Sol. No. 1 2 3 4 5 Volume of KI (ml) 20 18 15 12 10 [KI] K 0.195121951 0.00039 0.175609756 0.0004 0.146341463 0.0005 0.117073171 0.0006 0.097560976 0.0004 Log K Q1) Plot Log K' on y-axis and Log [KI] on x-axis A) Slope = B) Intercept = e) Log K = D) K = Log [KI] -3.40894 -0.70969387 -3.39794 -0.75545136 -3.30103 -0.834632606 -3.22185 -0.931542619 -3.39794 -1.010723865
tab esc slock ||| = OKINETICS AND EQUILIBRIUM Writing the rate law implied by a simple mechanism with an initi.... Suppose the formation of dinitrogen pentoxide proceeds by the following mechanism: step elementary reaction 1 NO₂ (g) + O₂ (g). -NO₂(g) + O₂(g) k₁ 2 NO₂ (g) + NO₂ (g) → N₂O5 (g) k₂ Suppose also k₁ «k₂. That is, the first step is much slower than the second. Write the balanced chemical equation for the overall chemical reaction. BE 1 Write the experimentally- observable rate law for the overall chemical reaction. Note: your answer should not contain the concentrations of any intermediates. Explanation Q A @ 2 Check W S X # 3 E 0 rate = k 14 D $ 4 rate constant > R F % 5 © Stv T MacBook Pro 6 G We Y & 7 H 0-0 U 00 Ⓒ2022 McGraw Hill LLC. All R You * 00 00 8 S a (
Please solve correctly, find value of x,y,z
(5) IV. Hydrogen and carbon monoxide react to give formaldehyde under certain conditions. H2(g) + CO(g) = HCHO(g) The mechanism proposed for this reaction is H2(g) = 2 H(g) H(g) + CO(g) H(g),+ HCO(g) → HCHO What rate law is derived from this mechanism? Step 1 Step 2 Step 3 fast HCO(g) slow > fast
Reaction Conc. Na2S½O3 Conc. HCI A Abs. A Time (s) Rate (A Abs./ga Time) 1.007568 0.300349 0.01870913 0.02870913 1 0.10 M .30 М 1.3686611 1.358380874 0.10 M .15 M 1.5360817 5.114311671 3 0.050 M .30 M 1.2267196 65.56796601 4 0.025 M .30 M 0.9563164 11.3085840 4. Use experimental data and the rate law to calculate a rate constant for each reaction 1, 2, 3, 4. How do the rate constants compare? Should they be the same or different? Discuss in your conclusions. Report the average value of your calculations. Be sure to include units in your rate constant. The rate law of the reaction is shown below: Rate = [Na2S2O3]-2
Answer the attached photo.

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