2N₂O,(soln) Rate Law: [N₂O3] (mol/L) Integrated Rate Law: 1.00 0.88 0.78 0.69 0.61 0.54 0.48 0.43 0.38 0.34 0.30 • Determine the order of reaction, half-life and rate constant Hint: Integrated rate laws for zero, first and second order reactions are shown below Order First Rate = K[A] In[A] -kr + In[A] Plot Needed to Give a Straight Line: Relationship of Rate Constant to the Slope of Straight Line: Half-Life: 4NO₂(soln) + O₂(g) Time (s) 0 200 400 600 800 1000 1200 1400 1600 1800 2000 Zero Rate = k [A] = -kr + [A] [A] versus r Slope-k [A] 2k In[A] versus t Slope--k 0.693 11/2² Second Rate = K[A]² kr + 11/2 [A] versus / [A] Slope-k A[A]
2N₂O,(soln) Rate Law: [N₂O3] (mol/L) Integrated Rate Law: 1.00 0.88 0.78 0.69 0.61 0.54 0.48 0.43 0.38 0.34 0.30 • Determine the order of reaction, half-life and rate constant Hint: Integrated rate laws for zero, first and second order reactions are shown below Order First Rate = K[A] In[A] -kr + In[A] Plot Needed to Give a Straight Line: Relationship of Rate Constant to the Slope of Straight Line: Half-Life: 4NO₂(soln) + O₂(g) Time (s) 0 200 400 600 800 1000 1200 1400 1600 1800 2000 Zero Rate = k [A] = -kr + [A] [A] versus r Slope-k [A] 2k In[A] versus t Slope--k 0.693 11/2² Second Rate = K[A]² kr + 11/2 [A] versus / [A] Slope-k A[A]
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
![2N₂O5(soln) 4NO₂(soln) + O₂(g)
Time (s)
0
200
400
600
800
1000
1.00
0.88
0.78
0.69
0.61
0.54
0.48
0.43
0.38
0.34
0.30
• Determine the order of reaction, half-life and rate constant
Rate Law:
[N₂O5] (mol/L)
Hint: Integrated rate laws for zero, first and second order reactions are shown below
Order
First
Rate = K[A]
In[A] -kr+ In[A]o
Integrated Rate Law:
Plot Needed to Give a Straight Line:
Relationship of Rate Constant
to the Slope of Straight Line:
Half-Life:
Zero
Rate = k
[A] = -kr + [A]o
[A] versus f
Slope-k
[A]
2k
1200
1400
1600
1800
2000
11/2 =
In[A] versus
Slope-k
0.693
k
11/2
Second
Rate = K[A]²
[A]
= kr +
A
Slopek
fyz
[A]o
versus /
=
K[A]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa78a0229-4b42-4ae7-95b8-ca59be1c3ef2%2F531c9e50-bfb5-47a0-8294-0116ff5b6488%2Fwddhxqj_processed.jpeg&w=3840&q=75)
Transcribed Image Text:2N₂O5(soln) 4NO₂(soln) + O₂(g)
Time (s)
0
200
400
600
800
1000
1.00
0.88
0.78
0.69
0.61
0.54
0.48
0.43
0.38
0.34
0.30
• Determine the order of reaction, half-life and rate constant
Rate Law:
[N₂O5] (mol/L)
Hint: Integrated rate laws for zero, first and second order reactions are shown below
Order
First
Rate = K[A]
In[A] -kr+ In[A]o
Integrated Rate Law:
Plot Needed to Give a Straight Line:
Relationship of Rate Constant
to the Slope of Straight Line:
Half-Life:
Zero
Rate = k
[A] = -kr + [A]o
[A] versus f
Slope-k
[A]
2k
1200
1400
1600
1800
2000
11/2 =
In[A] versus
Slope-k
0.693
k
11/2
Second
Rate = K[A]²
[A]
= kr +
A
Slopek
fyz
[A]o
versus /
=
K[A]
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